Answer:
Step-by-step explanation:
Let the two consecutive numbers be 2n and 2n+2
The sum of these numbers in 2n + (2n+2).
Hence
2n + (2n+2) = 34
4n + 2 = 34
4n = 32
n =8.
Answer:
What's the previous problem
Step-by-step explanation:
<u>EXPLANATION</u><u>:</u>
Given that
sin θ = 1/2
We know that
sin 3θ = 3 sin θ - 4 sin³ θ
⇛sin 3θ = 3(1/2)-4(1/2)³
⇛sin 3θ = (3/2)-4(1/8)
⇛sin 3θ = (3/2)-(4/8)
⇛sin 3θ = (3/2)-(1/2)
⇛sin 3θ = (3-1)/2
⇛sin 3θ = 2/2
⇛sin 3θ = 1
and
cos 2θ = cos² θ - sin² θ
⇛cos 2θ = 1 - sin² θ - sin² θ
⇛cos 2θ = 1 - 2 sin² θ
Now,
cos 2θ = 1-2(1/2)²
⇛cos 2θ = 1-2(1/4)
⇛cos 2θ = 1-(2/4)
⇛cos 2θ = 1-(1/2)
⇛cos 2θ = (2-1)/2
⇛cos 2θ = 1/2
Now,
The value of sin 3θ /(1+cos 2θ
⇛1/{1+(1/2)}
⇛1/{(2+1)/2}
⇛1/(3/2)
⇛1×(2/3)
⇛(1×2)/3
⇛2/3
<u>Answer</u> : Hence, the req value of sin 3θ /(1+cos 2θ) is 2/3.
<u>also</u><u> read</u><u> similar</u><u> questions</u><u>:</u> If sin Θ = 2/3 and tan Θ < 0, what is the value of cos Θ?
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if cos θ -sin θ =1, find θ cos θ +sin θ?
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First you would put both numbers into improper fractions.
3 1/3 = 10/3 and 2 1/4 = 9/4
Multiply 10/3 * 9/4
10*9 = 90 and 3 * 4 =12
So 90/12 is your fraction. Reduce it, 7 6/12
7 6/12 = 7 1/2
So your answer is 7 1/2
Hope I helped :)