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Digiron [165]
3 years ago
13

Every sixth visitor to an animal gets a free animal calendar.every twentieth visitor gets a free animal toy. which visitor each

day will be the first one to get both the calendar and the animal toy?
Mathematics
1 answer:
blondinia [14]3 years ago
8 0
The 60th customer each day will get both a calendar and a toy, as 60/20 = 3 and 60/6 = 10
You might be interested in
Which is another way to check the sum of 104 + 34 + 228 + 877?
weqwewe [10]

By adding 104+34 and then 228+877, Then adding both of the results and finally subtracting the answer by one of the factors.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Explanation:

Which will be...

104+34=138

228+877=1,105

Then add them...

138+1,105=1,243

Finally, subtract your answer by one of the factors...

1,243-1,105

Which will result as 138. Which is also one of the factors you added earlier, that's basically what your looking fro when checking and subtraction and/or addition problem.

5 0
3 years ago
Multiply: 1/6 * 2/3
AnnZ [28]
2/18 reduced = 1/9 that's my answer
3 0
4 years ago
Read 2 more answers
Could anyone please help me find k divided by 9 = 12 as well as 84n = 504 and 6 = m over 148? I need explanations...
Lana71 [14]
<u>k / 9  =  12</u>
Multiply each side of the equation by  9 :    <em>k = 108</em>

<u>84 n = 504</u>
Divide each side of the equation by  84 :      <em>n = 6</em>

<u>6 = m / 148</u>
Multiply each side of the equation by 148 :        <em>888 = m</em>
4 0
3 years ago
Evaluate - y + (- z) + 7.99 where y = 1.46 and z = 3.82
MA_775_DIABLO [31]

Answer:

2.71

Step-by-step explanation:

-y + (- z) + 7.99 =

= -(1.46) + [-(3.82)] + 7.99

= -1.46 - 3.82 + 7.99

= 2.71

7 0
3 years ago
Henry is standing on a bridge over a creek. If he could throw a stone straight up into the air with a velocity of 50 feet per se
Naddika [18.5K]
Henry is 20 feet above the water.  You want to know whether stone can reach
60 feet above the water.  So what you're really asking is:  Calculate whether
the stone can reach 40 feet above Henry, and we can forget about the creek ?

Call Henry's elevation zero, and the height of the stone at any time after
the toss 'H'.

Way back among the pages in your Physics book that are clean and shiny
because they have never yet been exposed to air or sunlight, you will find
the formula for the height of an object in free-fall:

Height = H₀ + V₀t + 1/2 A t²

H₀ = the object's height when it was released
V₀ = the object's speed when it was released, negtive if downward
A = the object's acceleration, negative if downward
t = time since the object was released

In the case that involves Henry on the bridge . . .

H₀ = 0
V₀ = +50 ft/sec
A = -32 ft/sec²  (acceleration due to gravity)

We want to know if the height of the object can ever be +40 feet.
We can plug all the numbers into the equation, and solve it.  Since the equation
is written in terms of ' t ', any solution we get will be a 'time'.  That's not what
we're looking for, but if there's any real solution, then we'll know that it's possible.

40 = 50t + 16t²

Subtract 40 from each side:

16t² + 50t - 40 = 0

Just to make the numbers more manageable, divide each side by 2 :

8t² + 25t - 20 = 0

Plug this into the quadratic formula:

t = (1/16) x (-25 plus or minus the square root of [625 - 640] )

Do you see that 'square root of -15 in there ?

The ' -15 ' is called the 'discriminant' of our quadratic equation, and
since it's negative, our equation has no real solutions ... there's no
such thing as the real square root of a negative number.

So the answer to the question is:  <u>No</u>. The stone never reaches a height
of 40 feet above Henry, or 60 feet above the creek.

Whew!
===============================================

A slightly easier way to do it:

Henry throws the stone upward at 50 ft/sec.
The acceleration of gravity is 32 ft/sec² downward.

The stone keeps rising for (50/32) = 1.5625 second, until its upward speed
has shrunk to zero, and then it starts falling.

How high is it when it stops rising ?

Its upward speed was 50 when Henry tossed it, and zero when it stopped rising.
Its average speed on the way up was (1/2)(50 + 0) = 25 ft/sec upward.

It has that average speed for 1.5625 seconds.
How far does it climb in that time ?

H = (25 ft/sec) x (1.5625 sec) = 39.0625 feet.

That's pretty close, but not quite 40 feet above Henry.
So the answer to the question is:  <u>No</u>.


7 0
3 years ago
Read 2 more answers
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