Dissolving sodium chloride will
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Answer:
The time taken for the commercial Jet liner to reach the end of its runway is 10.18 s.
Explanation:
Given;
average acceleration of the commercial Jet liner, a = 3g = 3 x 9.8 m/s² = 29.4 m/s²
distance traveled by the commercial Jet liner, s = 1542 m
The time taken for the commercial Jet liner to reach the end of its runway is calculated as follows;
s = ut + ¹/₂at²
where;
u is the initial velocity of the commercial Jet liner = 0
s = 0 + ¹/₂at²
s = ¹/₂at²
2s = at²
Therefore, the time taken for the commercial Jet liner to reach the end of its runway is 10.18 s.
Missing question:
"<span>What is his velocity? Please answer using two sig figs in m/s."
Solution
The relationship between velocity (v), space (S) and time (t) is
</span>
<span>The space covered by Harry is
</span>
<span>and so the velocity is
</span>
<span>
</span>
"<span>What is his velocity? Please answer using two sig figs in m/s."
Solution
The relationship between velocity (v), space (S) and time (t) is
</span>
<span>The space covered by Harry is
</span>
<span>and so the velocity is
</span>
</span>