6. What is Mass????????????????

How are longitudinal and transverse waves different?

Natalija [7]

Answer:

A longitudinal wave is a wave where the movement of the medium is in the same direction as the wave. On the other hand, a transverse wave is a wave where the movement of the medium is at a right angle to the wave direction.

Explanation:i got this right on a quiz so i know its right

3 0

3 years ago

Henrietta is going off to her physics class, jogging down the sidewalk at a speed of 2.70 m/s. Her husband Bruce suddenly realiz

Katen [24]

Answer:

The velocity is $v = 6.66 \ m/s$

Henrietta is at distance $s= 18.17 \ m$ from the under the window

Explanation:

From the question we are told that

The speed of Henrietta is $v= 2.70 \ m/s$

The height of the window from the ground is $h = 36.5 \ m$

Generally the time taken for the lunch to reach the ground assuming it fell directly under the window is

$t = \sqrt{\frac{2 * h }{g} }$

=> $t = \sqrt{\frac{2 * 36.5 }{9,8} }$

=> $t = 2.73 \ s$

Generally the time taken for the lunch to reach Henrietta is mathematically represented as

$T = t + t_1$

Here $t_1$ is the time duration that elapsed after Henrietta has passed below the window the value is given as 4 s

Now

$T = 2.73 + 4$

=> $T = 6.73 \ s$

Generally the distance covered by Henrietta before catching her lunch is

$s= v * T$

=> $s= 2.70 * 6.73$

=> $s= 18.17 \ m$

Generally the speed with which Bruce threw her lunch is mathematically represented as

$v = \frac{18.17}{2.73}$

$v = 6.66 \ m/s$

4 0

3 years ago

When a cube is inscribed in a sphere of radius r, the length Lof a side of the cube is . If a positive point charge Qis placed a

Nana76 [90]

Answer:

Ф_cube /Ф_sphere = 3 /π

Explanation:

The electrical flow is

Ф = E A

where E is the electric field and A is the surface area

Let's shut down the electric field with Gauss's law

Фi = ∫ E .dA = $q_{int}$ / ε₀

the Gaussian surface is a sphere so its area is

A = 4 π r²

the charge inside is

q_{int} = Q

we substitute

E 4π r² = Q /ε₀

E = 1 / 4πε₀ Q / r²

To calculate the flow on the two surfaces

* Sphere

Ф = E A

Ф = 1 / 4πε₀ Q / r² (4π r²)

Ф_sphere = Q /ε₀

* Cube

Let's find the side value of the cube inscribed inside the sphere.

In this case the radius of the sphere is half the diagonal of the cube

r = d / 2

We look for the diagonal with the Pythagorean theorem

d² = L² + L² = 2 L²

d = √2 L

we substitute

r = √2 / 2 L

r = L / √2

L = √2 r

now we can calculate the area of the cube that has 6 faces

A = 6 L²

A = 6 (√2 r)²

A = 12 r²

the flow is

Ф = E A

Ф = 1 / 4πε₀ Q/r² (12r²)

Ф_cubo = 3 /πε₀ Q

the relationship of these two flows is

Ф_cube /Ф_sphere = 3 /π

8 0

3 years ago

A mass weighting 48 lbs stretches a spring 6 inches. The mass is in a medium that exerts a viscous resistance of 27 lbs when the

Mademuasel [1]

Answer:

a)

$u(t)=0.499ft.e^{-\frac{144.76lb/s}{2(48lb)}t}cos(\omega t)\\\\u(t)=0.499ft.e^{-1.5t}cos(\omega t)$

b)

m = 48lb

c)

b = 144.76lb

Explanation:

The general equation of a damping oscillate motion is given by:

$u(t)=u_oe^{-\frac{b}{2m}t}cos(\omega t-\alpha)$ (1)

uo: initial position

m: mass of the block

b: damping coefficient

w: angular frequency

α: initial phase

a. With the information given in the statement you replace the values of the parameters in (1). But first, you calculate the constant b by using the information about the viscous resistance force:

$|F_{vis}|=bv\\\\b=\frac{|F_{vis}|}{v}\\\\|F_{vis}|=27lbs=27*32.17ft.lb/s^2=868.59ft.lb/s^2\\\\b=\frac{868.59}{6}lb/s=144.76lb/s$

Then, you obtain by replacing in (1):

6in = 0.499 ft

$u(t)=0.499ft.e^{-\frac{144.76lb/s}{2(48lb)}t}cos(\omega t)\\\\u(t)=0.499ft.e^{-1.5t}cos(\omega t)$

b.

mass, m = 48lb

c.

b = 144.76 lb/s

8 0

3 years ago

PLEASE HELP ME What does a moving charge experience when it is near a magnetic field? static friction gravity a stationary charg

attashe74 [19]

A moving charge experiences a force as it moves close to a magnetic field present in a region.

Explanation:

A charged particle when moves near a magnetic field is forced to move in a circular path. If there is a straight moving charged particle enters the region of the magnetic field, it's path is changed from straight path to the curved path.

The motion of the charged path inside or near the magnetic field will be a circular path and this circular path is due to the force experienced by the charged particle in the magnetic field.

The force experienced by the a charged particle as it moves near the magnetic field is termed as the Lorentz force. The expression for the Lorentz force experienced by the charged particle in the magnetic field is given by:

$\boxed{F_m=Q(\overrightarrow{v}\times\overrightarrow{B})}$

Here, $F_m$ is the magnetic force, $Q$ is the amount of charge, $\overrightarrow{v}$ is the velocity vector and $\overrightarrow{B}$ is the magnetic field intensity in the region.