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ololo11 [35]
3 years ago
7

How has the farming industry been affected by the use of fossil fuels?

Physics
1 answer:
Mashutka [201]3 years ago
3 0

Fossil fuels have led to an increase in food costs.

Explanation:

Buried organic material over million of years form combustible geologic deposits of organic materials called fossil fuels that can be converted crude oil, natural gas, or coal.

Fossil fuel are currently used as a source of energy in machine and equipment applied in the farming industry. Mechanization has been made possible due to this type of fuel availability thus larger farms have been prepared for cultivation.In addition, other processes such as planting,weeding and harvesting are currently performed by farming machines which are propelled by fossil energy. So in general, fossil fuels in the farming industry has led to increase in amount of crop harvested because more farms are under cultivation and farming process is now mechanized. However, due to use of machines and energy, the production cost has increased, thus to cover for this increased cost, the prices for food products increases, making the cost of food commodities to rise.

Learn More

Fossil fuels: brainly.com/question/13660400

Keyword: Farming, industry, fossil fuel

#LearnwithBrainly

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A cylinder with a piston contains 0.200 mol of oxygen at 2.00×105 Pa and 360 K . The oxygen may be treated as an ideal gas. The
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C. \Delta U=1512\ J

D. W=0\ J

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Given:

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  • initial pressure in the cylinder, P_i=2\times 10^5\ Pa
  • initial temperature of the gas in the cylinder, T_i=360\ K

<em>According to the question the final volume becomes twice of the initial volume.</em>

<u>Using ideal gas law:</u>

P.V=n.R.T

2\times 10^5\times V_i=0.2\times 8.314\times 360

V_i=0.003\ m^3

A.

<u>Work done by the gas during the initial isobaric expansion:</u>

W=P.dV

W=P_i\times (V_f-V_i)

W=2\times 10^5\times (0.006-0.003)

W=600\ J

C.

<u>we have the specific heat capacity of oxygen at constant pressure as:</u>

c_v=21\ J.mol^{-1}.K^{-1}

Now we apply Charles Law:

\frac{V_i}{T_i} =\frac{V_f}{T_f}

\frac{0.003}{360} =\frac{0.006}{T_f}

T_f=720\ K

<u>Now change in internal energy:</u>

\Delta U=n.c_p.(T_f-T_i)

\Delta U=0.2\times 21\times (720-360)

\Delta U=1512\ J

B.

<u>Now heat added to the system:</u>

Q=W+\Delta U

Q=600+1512

Q=2112\ J

D.

Since during final cooling the process is isochoric (i.e. the volume does not changes). So,

W=0\ J

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