Answer: The most likely identity of the substance is iron.
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
Q = Heat absorbed=
Joules
m= mass of substance = 11.9 g
c = specific heat capacity = ?
Initial temperature of the water = 
= 25.0°C
Final temperature of the water = 
= 45.0°CChange in temperature ,
Putting in the values, we get:
The specific heat of 0.45 is for iron and thus the substance is iron.
1km=10^3 m,1km^3=10^9cubic metres answer is 1.4x10^18cubic meters
Answer:
The World Is Pure Enough as it is that we don't melt or (lose air) \_/
Explanation:
All people don't have to be concerned about is a disruption of the plethora of gases we already have in our atmosphere and trees need C02 in order to breath and that's what cows produce that's what we breath out and what coal plants and fossil fuels produce the more C02 the more trees produce oxygen because trees breathe in C02 and pop out Oxygen and plus power plants don't produce C02 they produce water vapor so (ALL IN ALL C02 Will not cause the Ice Caps to melt because trees already have that issue covered that's why the scientists said they fixed the global warming issue to keep people from whining about a non-existent problem. so basically its true The greenhouse effect does keep the earth warm halfly because of the hot gases that get trapped in the atmosphere like C02.True
The answer is false, your welcome.
Answer:
the rate of flow = 29.28 ×10⁻³ m³/s or 0.029 m³/s
Explanation:
Given:
Diameter of the pipe = 100mm = 0.1m
Contraction ratio = 0.5
thus, diameter at the throat of venturimeter = 0.5×0.1m = 0.05m
The formula for discharge through a venturimeter is given as:
Where,
is the coefficient of discharge = 0.97 (given)
A₁ = Area of the pipe
A₁ = 
A₂ = Area at the throat
A₂ = 
g = acceleration due to gravity = 9.8m/s²
Now,
The gauge pressure at throat = Absolute pressure - The atmospheric pressure
⇒The gauge pressure at throat = 2 - 10.3 = -8.3 m (Atmosphric pressure = 10.3 m of water)
Thus, the pressure difference at the throat and the pipe = 3- (-8.3) = 11.3m
Substituting the values in the discharge formula we get
or
or
Q = 29.28 ×10⁻³ m³/s
Hence, the rate of flow = 29.28 ×10⁻³ m³/s or 0.029 m³/s
