Answer:
C - 19/24
Step-by-step explanation:
Take the fractions and put the denominators into a common factor


Add Numerators Across


Answer:
Step-by-step explanation:
c and d
Answer:
h(x)
Step-by-step explanation:
to solve for an inverse, you swap the x and the y and then solve for y
f(x) = 4x^3-8
y = 4x^3 - 8
x = 4y^3 - 8 swap the x and y
now solve for y:
x + 8 = 4y^3
(x + 8)/4 = y^3
1/4x + 8/4 = y^3
1/4x + 2 = y^3
y = ![\sqrt[3]{1/4x + 2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1%2F4x%20%2B%202%7D)
start with the ones and every time it goes over ten take the first number and add it to the tens for example 1+8+4+8=21 take the one and put it in the one spot below. Then take the 2 and add it to the six in the tens spot so it would be Instead of 6+8+3+2 it would be 8+8+3+2 which would equal 21 then put the 1 u=in the ten spot below add the 2 to the hundreds spot making is 5+5+7=4=14 put the 4 Below and add the 1 the the thousands making it 3+4+5+1=13 put the one on the ten thousands and put the three below the whole problem would be 13,411.