We know that imaginary roots always come in pairs, so we already know 4 solutions
-2, 2, 4 + i and a pair of 4 + i
Since imaginary roots always come in pairs we wont have more than 2 imaginary roots, since its a fifth degree root and we can only have 5 roots
So for sure, we will have 3 real roots and 2 imaginary roots
Last option, f(x) has three real roots and two imaginary roots
Answer:
here is the answer
Step-by-step explanation:
So first you plug in (8,3) into their respective places, which makes it:
3= 5(8)-7
Solve
3 = 40-7
3 does not equal 33,
So the answer is no
