Answer:
(a) The confidence interval is: 0.0304 ≤ π ≤ 0.0830.
(b) Upper confidence bound = 0.0787
Step-by-step explanation:
(a) The confidence interval for p (proportion) can be calculated as


NOTE: π is the proportion ot the population, but it is unknown. It can be estimated as p.

For a 95% two-sided confidence interval, z=±1.96, so

The confidence interval is: 0.0304 ≤ π ≤ 0.0830.
(b) The confidence interval now has only an upper limit, so z is now 1.64.

The confidence interval is: -∞ ≤ π ≤ 0.0787.
You have to multiply 4 decimal 5 * 2 and you get your answer and 0.7 * 2 and then you add up those two answers such a bit and see what you get
Easy!!!!! its zero!!!!! LOL
Answer: A and D
Step-by-step explanation:
Table B : not a function the value of x=3 has two images
Table C: not a function the value of x=1 has two images
Tables A and D are functions
Exponential laws

so
(m^(2/3))^(1/2)=m^(2/3 times 1/2)=m^(2/6)=m^(1/3)=
![\sqrt[3]{m^{1}}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bm%5E%7B1%7D%7D%20)
=