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Paraphin [41]
3 years ago
13

Thirteen more than the quotient of twenty and four

Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
8 0

Answer:

19

Step-by-step explanation:

20/4 + 13

20/4 = 6

6+13 = 19

vesna_86 [32]3 years ago
3 0

Answer:

The equation is 13 + \frac{20}{4} <em>or</em> 13 + (20 ÷ 4)

The answer is 13 + 5 = 18

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Mrs. Santos is buying binders for the students in her class. She determined that 15 binders would cost $22.50.
atroni [7]

Answer:

It will cost $42 for 28 binders

Step-by-step explanation:

We know that 15 binders = 22.50 dollars . We need to find the cost of 18, 30, 28, and 48 binders to figure out if they match up with the statements. One way to do this is to find the cost for one binder, and then multiply that by the number of binders to find the cost for a certain number of binders. For example, if one binder costs 2 dollars, five binders would cost 2 * 5 = 10 dollars.

To figure out how much one binder costs, we can use the division property of equality to divide both sides of our equation (15 binders = 22.50 dollars) by 15. We divide by 15 because anything divided by itself is equal to 1, and that would make it 1 binder = something dollars.

Applying this, we get

(15 binders)/15 = (22.5 dollars)/15

1 binder = 1.5 dollars

For 18 binders, this would cost 1.5 * 18 = 27 dollars. We know this because we add 1.5 dollars for each binder.

For 30 binders, this would cost 30*15=45 dollars

For 28 binders, this would cost 1.5 * 28 = 42 dollars

For 48 binders, this would cost 1.5*48 = 72 dollars

The only one that matches up is 28 binders for 42 dollars

8 0
3 years ago
6,657 ÷ 6 = Whats the answer and if there is a remander what is the remander
sdas [7]
The answer is 1,109.5
8 0
3 years ago
Read 2 more answers
Find the maximum value or minimum value for the function f(x) = 0.15(x + 1)² - 3.
il63 [147K]

Answer:

The minimum value for  f(x) = 0.15(x + 1)^2 - 3 is -3.

Step-by-step explanation:

Given function is f(x) = 0.15(x + 1)^2 - 3

We need to find the maximum value or the minimum value for the function.

Now, differentiate f(x) = 0.15(x + 1)^2 - 3  w.r.t x.

f'(x) =\frac{d}{dx}(0.15(x + 1)^2 - 3)\\f'(x)=\frac{d}{dx}(0.15(x+1)^2-\frac{d}{dx}(3)\\

f'(x)=2\times 0.15(x+1)\frac{d}{dx}(x+1)-0\\f'(x)=0.3(x+1)(1)\\f'(x)=0.3(x+1)

Now, we will equate f'(x)=0 to find critical point.

0.3(x+1)=0\\x=-1

Plug this critical point in to the function f(x) = 0.15(x + 1)^2 - 3  we get,

f(-1) = 0.15(-1 + 1)^2 - 3\\f(-1)=-3

Also, f''(x)=0.3 which is positive, We have minimum value.

So, the minimum value for  f(x) = 0.15(x + 1)^2 - 3 is -3.

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IrinaVladis [17]

Answer:28.26

Step-by-step explanation:9 x 3.14

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3 years ago
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Step-by-step explanation:

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