-3 (2m+5)+8=5 (-2m+1)
2 answers:
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Other method:
zeros of numerator and denominator are x = -2 and x = 4.
Look at the second picture.
for x < -2 → x + 2 < 0 and x - 4 < 0
therefore
for -2 < x < 4 → x + 2 > 0 and x - 4 < 0
therefore
for x > 4 → x + 2 > 0 and x - 4 > 0
therefore
Answer: b= 11.2
10^2 + b^2 = 15^2
100 + b^2 = 225
b^2 = 125
b=
b= 11.2
Step-by-step explanation:
QP=24 cm
RS=11.25 cm
QS=18.75 cm
<u>Explanation</u>:
Given that TQ bisects <RTP
(1)
consider ΔRQS and ΔRPT
QS||PT,RP and RT are transversals
(alternate angles)(2)
comparing (1) and (2)
and triangle SQT is isocelus
Therefore SQ=ST(sides opposite to equal angles in an isocelus triangle)
Therefore <RQS=<RPT(corresponding angles)
<RSQ=<RTP(corresponding angles)
therefore by AA criterion for similarity
ΔRQS~ΔRPT
According to the property of similar triangles
Answer:
0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Coin chosen from box B is red.
Event B: Blue poker chip transferred.
Probability of choosing a red coin:
7/10 of 4/9(red coin from box A)
6/10 of 5/9(blue coin from box A). So
Blue chip transferred, red coin chosen:
6/10 of 5/9. So
What is the probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red?
0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red