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White raven [17]
2 years ago
7

(09.04 mc) a circle has its center at (−1, 2) and a radius of 3 units. what is the equation of the circle? (x − 1)2 + (y + 2)2 =

3 (x + 1)2 + (y − 2)2 = 3 (x + 1)2 + (y + 2)2 = 9 (x + 1)2 + (y − 2)2 = 9
Mathematics
2 answers:
zheka24 [161]2 years ago
8 0

Answer:

The answer is the last one (x+12+(y-2)2=9

Step-by-step explanation:

Reil [10]2 years ago
4 0
General formula to make an equation of circle
(x - a)² + (y - b)² = r²


Given:
the center (a,b) = (-1,2)
the radius r = 3

Solution:
plug the numbers to the formula
(x - a)² + (y - b)² = r²
(x - (-1))² + (y - 2)² = 3²
(x + 1)² + (y - 2)² = 9
The answer is the last option
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As his empire spread throughout the ancient world, Alexander founded roughly how many cities?
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Express this in standard form 5.4×10^1​
Naily [24]
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Find the 61st term of -12, -28, -44,
Citrus2011 [14]

Answer:

a_{61}=-972

Step-by-step explanation:

<u>Arithmetic Sequences</u>

The arithmetic sequences are identified because any term n is obtained by adding or subtracting a fixed number to the previous term. That number is called the common difference.

The equation to calculate the nth term of an arithmetic sequence is:

a_n=a_1+(n-1)r

Where

an = nth term

a1 = first term

r   = common difference

n  = number of the term

We are given the first terms of a sequence:

-12, -28, -44,...

Find the common difference by subtracting consecutive terms:

r = -28 - (-12) = -16

r = -44 - (-28) = -16

The first term is a1 = -12. Now we calculate the term n=61:

a_{61}=-12+(61-1)(-16)

a_{61}=-12-60*16=-12-960

\mathbf{a_{61}=-972}

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What is the common point between lines y = -x + 7 and y = 3x + 10?
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