There are a total of 8 letters in student, with 6 different letters ( there are 2 s's and 2 t's).
First find the number of arrangements that can be made using 8 letters.
This is 8! which is:
8 x 7 x 6 x 5 x 4 3 x 2 x 1 = 40,320
Now there are 2 s's and 2 t's find the number of arrangements of those:
S = 2! = 2 x 1 = 2
T = 2! = 2 x 1 = 2
Now divide the total combinations by the product of the s and t's:
40,320 / (2*2)
= 40320 / 4
= 10,080
The answer is A. 10,080
Answer: Choice E
multiply to give a*c and add to get b
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This is known as the AC factoring method based on how you multiply the first and last coefficients (a and c) and use that product to figure out which factors add to the middle coefficient.
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An example:
6x^2 + 35x + 50
We have a = 6, b = 35, c = 50
Multiply a and c and we get: a*c = 6*50 = 300
We need to find factors of 300 that pair up and add to 35
Through trial and error you should find,
15 * 20 = 300
15 + 20 = 35
The two numbers are therefore 15 and 20.
So we break 35x into 15x+20x and use the factor by grouping method
6x^2 + 35x + 50
6x^2 + 15x + 20x + 50
(6x^2 + 15x) + (20x + 50)
3x(2x + 5) + 10(2x + 5)
(3x + 10)(2x + 5)
We see that 6x^2 + 35x + 50 factors to (3x + 10)(2x + 5)
Use the FOIL method or the box method or distribution to help see that (3x + 10)(2x + 5) expands back to 6x^2 + 35x + 50.
Answer:
the anwer is a triangle as it is shown below.
Answer:
d = vt
Step-by-step explanation:
Step 1: Write equation
v = d/t
Step 2: Multiply both sides by t
vt = d
Step 3: Rewrite
d = vt
Answer:
number of dimes is 8
number of quarters is 15
Step-by-step explanation:
let 'd' = number of dimes
let 'd+7' = number of quarters
.10d + .25(d + 7) = 4.55
.10d + .25d + 1.75 = 4.55
.35d = 2.80
d = 8
q = 7 + 8
