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Karo-lina-s [1.5K]
3 years ago
8

Francois baked just enough cookies to fill all the orders at his bakery. While the cookies were cooling, a kitchen assistant kno

cked over a cooling rack and spilled %12, percent of the cookies onto the floor. Francois had to bake 36 more cookies to replace them. How many cookies were ordered in total?
Mathematics
1 answer:
Ann [662]3 years ago
3 0
300 cookies were ordered to start. 

We can tell this because we know 12% is equal to 36. Because this is true, we can set up a proportion to solve. All proportions can be set up with the small number on top and the total on the bottom. This will help you solve for the missing number, which is in this case the total number of cookies.  Let x be the total number of cookies.  

Percentage/total percentage = cookies/cookies total 
12/100 = 36/x

Now we can cross multiply to solve. 
(100)(36) = (12)(x) ----> multiply 
3600 = 12x ---> divide by 12
300 = x
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X= 5.1x+11.3
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3 years ago
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Evaluate using the finite geometric sum formula
Sever21 [200]

Answer:

S_9=-18.703.

Step-by-step explanation:

The given series is,

\sum_{i=1}^9(-\frac{1}{2})^{i-1}

When we substitute i=1, we get the first term, which is a_1=-28(-\frac{1}{2})^{1-1}


This implies that,

a_1=-28(-\frac{1}{2})^{0}


a_1=-28(1)=-28.


The common ratio is

r=-\frac{1}{2}


The finite geometric sum is given by the formula,

S_n=\frac{a_1(r^n-1)}{r-1} , -1\:.


Since there are 9 terms, we find the sum of the first nine terms by putting n=9 in to the formula to get,


S_9=\frac{-28((-\frac{1}{2})^9-1)}{-\frac{1}{2}-1}.


S_9=\frac{-28((-\frac{1}{2})^9-1)}{-\frac{1}{2}-1}.


S_9=\frac{-28((-\frac{1}{512})-1)}{-\frac{3}{2}}.


S_9=\frac{-28(-\frac{513}{512})}{-\frac{3}{2}}.


S_9=-28(\frac{171}{256}).


S_9=-\frac{1197}{64}.



S_9=-18.703.


The correct answer is B





4 0
3 years ago
Read 2 more answers
Plz help...................
gtnhenbr [62]
Your answer will be 23√3

if the numbers inside the √  is the same, then you can add the outside ones together

in this case it will be 23√3

hope this helps
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A rectangular storage container with an open top is to have a volume of 10 m3. The length of this base is twice the width. Mater
Lelechka [254]
L=2W, V=LWH using L=2W in the Volume equation we get:

V=2W^2H and V=10 so

10=2W^2H  now we can solve this for H

H=5/W^2 and L=2W  we'll need these later :)

C=20LW+12*2LH+12*2WH

C=20LW+24LH+24WH  using our H and L found earlier...

C=20(2W^2)+24(2W*5/W^2)+24(W*5/W^2)

C=40W^2+240/W+120/W  making a common denominator...

C=(40W^3+240+120)/W

C=(40W^3+360)/W

dC/dW=(120W^3-40W^3-360)/W^2

dC/dW=(80W^3-360)/W^2

d2C/dW2=(240W^4-160W^4+720W)/W^4

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Since d2C/dW2 is positive for all possible values of W (as W>0), when dC/dW=0, C(W) will be at an absolute minimum value...

dC/dW=0 only when 80W^3-360=0

80W^3=360

W^3=45

So our minimum cost is:

C(45^(1/3))=(40W^3+360)/45^(1/3)

C(45^(1/3))=(40*45+360)/45^(1/3)

C(45^(1/3))=2160/45^(1/3)

C≈$607.27  (to the nearest cent)


8 0
4 years ago
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