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bagirrra123 [75]
3 years ago
12

True or false? In a two-column proof, the right column states your reasons

Mathematics
1 answer:
lisov135 [29]3 years ago
8 0
It is true because right is the reasons and left are the statements.

Hope this helps :)
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6x+3y=15 .What does y equal if x=2 ?if x=5
bezimeni [28]
_Award brainliest if helped!
if x =2 ,  6(2) + 3y = 15 
3y = 15-12
y = 1
if x=5, 6(5) + 3 y = 15
3y = -15
 y= -5
8 0
3 years ago
Rachel earned $23,750 and paid a FICA tax of 7.65%. How much FICA tax did she pay?
MAVERICK [17]
Tax = 7.65% of $23, 750

Tax = 0.0765 x 23750

Tax = $1816.88 (nearest hundredth)

------------------------------------------------------
Rachel needs to pay $1816.88 for FICA tax
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7 0
3 years ago
The school council was having a bake sale. Jaime purchased a brownie for $0.75, a
Ghella [55]

Answer: the answer is 2.75 because

Step-by-step explanation: 1.25+0.75+0.75=2.75 hope i Helped mark me as brainliest

4 0
3 years ago
A function f(x)=3x+12.
seraphim [82]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2822258

_______________


•  Function:   f(x) = 3x + 12.


A.  Finding the inverse of f.

The composition of f with its inverse results in the identity function:

(f o g)(x) = x

f[ g(x) ] = x

3 · g(x) + 12 = x

3 · g(x) = x – 12

              x – 12
g(x)  =  ⸺⸺
                 3

               x 
g(x)  =  ⸺  –  4    <———    this is the inverse of f.
               3

________


B.  Verifying that the composition of f and g gives us the identity function:

•  \mathsf{(f\circ g)(x)}

\mathsf{=f\big[g(x)\big]}\\\\\\ \mathsf{=3\cdot \left(\dfrac{x}{3}-4\right)+12}\\\\\\&#10;\mathsf{=\diagup\hspace{-7}3\cdot \dfrac{x}{\diagup\hspace{-7}3}-3\cdot 4+12}\\\\\\&#10;\mathsf{=x-12+12}\\\\&#10;\mathsf{=x\qquad\quad\checkmark}


and also

•  \mathsf{(g\circ f)(x)}

\mathsf{=g\big[f(x)\big]}\\\\\\ \mathsf{=\dfrac{f(x)}{3}-4}\\\\\\ \mathsf{=\dfrac{3x+12}{3}-4}\\\\\\&#10;\mathsf{=\dfrac{\diagup\hspace{-7}3\cdot (x+4)}{\diagup\hspace{-7}3}-4}\\\\\\&#10;\mathsf{=x+4-4}\\\\&#10;\mathsf{=x\qquad\quad\checkmark}

________


C.  Since f and g are inverse, then

f(g(– 2))

= (f o g)(– 2)

= – 2          <span>✔
</span>

•  Call h the compositon of f and g. So,

h(x) = (f o g)(x)

h(x) = x


As you can see above, there is no restriction for h. Therefore, the domain of h is R (all real numbers).


I hope this helps. =)

5 0
3 years ago
In triangle , side and the perpendicular bisector of meet in point , and bisects . If and , what is the area of triangle
stich3 [128]

In triangle ABC, side AC and the perpendicular bisector of BC meet in point D, and BD bisects ∠ABC。 If AD = 9 and DC = 7, 145–√5  is the area of a triangle.

I supposed here that [ABD] is the perimeter of ▲ ABD.

As  BD  is a bisector of  ∠ABC ,

ABBC=ADDC=97

Let  ∠B=2α

Then in isosceles  △DBC

∠C=α

BC=2∗DC∗cosα=14cosα

Thus  AB=18cosα

The Sum of angles in  △ABC  is  π  so

∠A=π−3α

Let's look at  AC=AD+DC=16 :

AC=BCcosC+ABcosA

16=14cos2α+18cosαcos(π−3α)

[1]8=7cos2α−9cosαcos(3α)

cos(3α)=cos(α+2α)=cosαcos(2α)−sinαsin(2α)=cosα(2cos2α−1)−2cosαsin2α=cosα(4cos2α−3)

With  [1]

8=cos2α(7−9(4cos2α−3))

18cos4−17cos2α+4=0

cos2α={12,49}

First root lead to  α=π4  and  ∠BDC=π−∠DBC−∠C=π−2α=π2 . In such case  ∠A=π−∠ABD−∠ADB=π4, and  △ABD  is isosceles with  AD=BD. As  △DBC  is also isosceles with  BD=DC=7,  AD=7≠9.

Thus first root  cos2α=12  cannot be chosen and we have to stick with the second root  cos2α=49. This gives  cosα=23  and  sinα=5√3.

The area of a triangle ABD=12h∗AD  where h  is the distance from  B  to  AC.

h=BCsinC=14cosαsinα

Area of  triangle ABD=145–√5

= 145–√5.

Incomplete question please read below for the proper question.

In triangle ABC, side AC and the perpendicular bisector of BC meet in point D, and BD bisects ∠ABC。 If AD = 9 and DC = 7, what is the area of triangle ABD?

Learn more about the Area of the triangle at

brainly.com/question/23945265

#SPJ4

6 0
2 years ago
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