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3 years ago

Division number into a fraction

Mathematics

1 answer:

Lesechka [4]3 years ago

5 0

Answer:

See below.

Step-by-step explanation:

To divide a fraction by a number, rewrite the number as a fraction by writing the number over one. Then do division of fractions.

Example:

$\dfrac{6}{7} \div 5 =$

Rewrite the number as a fraction.

$= \dfrac{6}{7} \div \dfrac{5}{1}$

Now divide the fractions by multiplying the first fraction by the reciprocal of the second fraction.

$= \dfrac{6}{7} \times \dfrac{1}{5}$

Multiply the numerators together. Multiply the denominators together.

$= \dfrac{6 \times 1}{7 \times 5}$

$= \dfrac{6}{35}$

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n200080 [17]

Answer:

Step-by-step explanation:

$f(x)=4x^2+4x-4\ or\ f^*(x)=4x+4x-4=8x-4\\\\f(0)-\text{put}\ x=0\ \text{to}\ f(x):\\\\f(0)=4(0)^2+4(0)-4=4(0)+0-4=0-4=-4\\\\f^*(0)=8(0)-4=0-4=-4$

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3 years ago

3x²-9x+1+0 Find the discriminant

Sindrei [870]

Answer:

$\boxed{D = 69}$

Step-by-step explanation:

The given quadratic equation is:

$3x^2-9x+1 = 0$

Comparing it with the standard form of Quadratic Equation $ax^2+bx+c = 0$ , we get:

a = 3, b = -9 and c = 1

Discriminant = b² - 4ac

D = (-9)²-4(3)(1)

D = 81 - 12

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3 years ago

Show how you got the answer

rewona [7]

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3 years ago

A company manufactures televisions. The average weight of the televisions is 5 pounds with a standard deviation of 0.1 pound. As

Semenov [28]

Answer:

$0.2564\text{ pounds}$

Step-by-step explanation:

The 90th percentile of a normally distributed curve occurs at 1.282 standard deviations. Similarly, the 10th percentile of a normally distributed curve occurs at -1.282 standard deviations.

To find the $X$ percentile for the television weights, use the formula:

$X=\mu +k\sigma$ , where $\mu$ is the average of the set, $k$ is some constant relevant to the percentile you're finding, and $\sigma$ is one standard deviation.

As I mentioned previously, 90th percentile occurs at 1.282 standard deviations. The average of the set and one standard deviation is already given. Substitute $\mu=5$ , $k=1.282$ , and $\sigma=0.1$ :

$X=5+(1.282)(0.1)=5.1282$

Therefore, the 90th percentile weight is 5.1282 pounds.

Repeat the process for calculating the 10th percentile weight:

$X=5+(-1.282)(0.1)=4.8718$

The difference between these two weights is $5.1282-4.8718=\boxed{0.2564\text{ pounds}}$ .

8 0

3 years ago

Read 2 more answers

The Amazon rainforest is gradually being destroyed by pollution and agricultural and industrial development. For simplicity, sup

KATRIN_1 [288]

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3 years ago