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zloy xaker [14]
3 years ago
8

What is (-4) raised to the negative third power?

Mathematics
2 answers:
Usimov [2.4K]3 years ago
7 0
-4(-4) = positive 16
Positive 16(-4) = -64
-64 is your answer
Annette [7]3 years ago
6 0

Answer:

-0.015625 that's the answer

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elena-14-01-66 [18.8K]
The addition property of equality justifies this. You could also say that she simply subtracted 7, and then it would be the subtraction property of equality. This is the case because if you add or subtract (or multiply or divide) the same number on both sides of an equation, the equation will still be the same.


Hope it helps!
5 0
3 years ago
Which number should replace the question mark in the number grid below?
-Dominant- [34]
B. 5

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In a certain town, the amount of sulfur oxide in the air, S, in tons, is related to the town’s population, P, in people. The rel
Lady bird [3.3K]

Answer:

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

Step-by-step explanation:

Data provided in the question:

Relation between the amount of sulfur oxide in the air and the population as:

S² = 110P² + 20P + 600

Population growth rate, \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

Now,

change in sulfur oxide with time i.e \frac{\textup{dS}}{\textup{dt}}

differentiating the given relation with respect to time 't'

we have

2S\frac{\textup{dS}}{\textup{dt}} =  2\times110P\frac{\textup{dP}}{\textup{dt}}  + 20

at P = 100 and  \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

we have

2S\frac{\textup{dS}}{\textup{dt}} = 2 × 110 × 100 × 10 + 20

or

2S\frac{\textup{dS}}{\textup{dt}} = 220020

or

\frac{\textup{dS}}{\textup{dt}} = \frac{\textup{220020}}{\textup{2S}}

or

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

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Step-by-step explanation:

5 0
3 years ago
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Answer:

answer is 2

Step-by-step explanation:

if you create an equation: (s+4)x2 = boris          s-1x12 = opa

only one that only works out is 2        

               

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