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marissa [1.9K]
2 years ago
5

What is the answer I have to type in the yellow boxes?

Mathematics
2 answers:
kap26 [50]2 years ago
7 0

\\ \rm\bull\rightarrowtail y=(1x^2)+3(x)

\\ \rm\bull\rightarrowtail y=1(-6)^2+3(-6)

\\ \rm\bull\rightarrowtail y=1(36)+(-18)

Note the rule

  • (+)(-)=(-)

\\ \rm\bull\rightarrowtail y=36-18

\\ \rm\bull\rightarrowtail y=18

hichkok12 [17]2 years ago
5 0

Answer:

36     -18

18

Step-by-step explanation:

This is slightly confusing, since the question says "find the y coordinate if x = -4" yet underneath if appears they want x = -6 !

If x = -6

Substitute -6 into the equation in place of x

⇒ y = 1 × (-6)² + 3(-6)

Apply the rule (-a)² = a²  and  a(-b) = -ab:

⇒ y = 1 × (6)² + -3×6

⇒ y = 1 × 36 + -18

Using order of operations, carry out the multiplication first:

⇒ y = 36 + -18

Then the addition (subtraction)

⇒ y = 36 - 18

⇒ y = 18

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For the given line segment, write the equation of the perpendicular bisector.
Jlenok [28]

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D) y = -4/5x – 47/10

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Step 1. Find the <em>midpoint of the segmen</em>t.

The two end points are (-6, -4) and (-2, 1).

The midpoint is at the average of the coordinates.

(xₚ, yₚ) = ((x₁ + x₂)/2, (y₁ + y₂)/2)

(xₚ, yₚ) = ((-6 - 2)/2, (-4 + 1)/2)

(xₚ, yₚ) = (-8/2, -3/2)

(xₚ, yₚ) = (-4, -3/2)

===============

Step 2. Find the <em>slope (m₁) of the segment</em>

m₁ = (y₂ - y₁)/(x₂ - x₁)

m₁ = (1 - (-4))/(-2 - (-6))

m₁ = (1 + 4)/(-2 + 6)

m₁ = 5/4

===============

Step 3. Find the <em>slope (m₂) of the perpendicular bisector </em>

m₂ = -1/m₁

m₂ = -4/5

====================

Step 4. Find the <em>intercept of the perpendicular bisector</em>

y = mx + b

y = -(4/5)x + b

The line passes through (-4, -3/2).

-3/2 = -(4/5)(-4) + b

-3/2 = 16/5 + b      Multiply each side by 10

 -15 = 32 + 10 b    Subtract 32 from each side

 -47 = 10b             Divide each side by 10

    b = -47/10

===============

Step 5. Write the <em>equation for the perpendicular bisector</em>

y = -4/5x – 47/10

The graph shows the midpoint of your segment at (-4, -3/2) and the perpendicular bisector passing through the midpoint and (0, -47/10).

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3 years ago
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