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Phantasy [73]
3 years ago
7

Solve for x 38=3x+35

Mathematics
2 answers:
olganol [36]3 years ago
6 0

Answer:

x = 1

Step-by-step explanation:

Keep the variable left alone by removing any numbers next to it-

3x = 33

Divide each side by 3 to keep x by itself

3x/3 = x

3/3 = 1

x = 1

Simplify-

x = 1

umka2103 [35]3 years ago
4 0

Answer:

\displaystyle 1 = x

Step-by-step explanation:

  38 = 3x + 35

- 35         - 35

______________

\displaystyle \frac{3}{3} = \frac{3x}{3} \\ \\ 1 = x

I am joyous to assist you anytime.

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2x+5=10<br> I need to find out x pls help​
Finger [1]

Answer:

5

Step-by-step explanation:

2x + 5 = 10

you minus the 5

2x = 5

you divide both sides by 2

x = 5

7 0
3 years ago
Read 2 more answers
E is the midpoint of DF, DE = 2x + 4, and EF = 3x + 1. Find DE, EF, and DF.
Agata [3.3K]
When there is a midpoint in a line segment, the two segments that are then produced have to be equal. So that means that because E is a midpoint of DF, DE=EF.
Set up the equation.
DE=EF
2x+4=3x+1
Then solve for x.
x=3
Then plug it back in the equation to find DE and EF.
DE=2x+4=2(3)+4=10
Because DE=EF then EF is also 10.
DF is made from the addition of DE and EF so DF is twice EF.
DF= 20

DE= 10, EF= 10, DF= 20

Hope this helps.
8 0
3 years ago
I need help with all these problems and need to know is the ones I did correct
kolezko [41]
Isabelle has a leash for her dog in the backyard. The leash is attached to a post which allows thedog to travel in a circle around the post. The leash is 3 feet long. How much of the yard can thedog reach while on the leash?

5 0
3 years ago
Please help me thank you
Hoochie [10]

Answer:

\large\boxed{\sin2\theta=\dfrac{\sqrt3}{2},\ \cos2\theta=\dfrac{1}{2}}

Step-by-step explanation:

We know:

\sin2\theta=2\sin\theta\cos\theta\\\\\cos2\theta=\cos^2\theta-\sin^2\thet

We have

\sin\theta=\dfrac{1}{2}

Use \sin^2\theta+\cos^2\theta=1

\left(\dfrac{1}{2}\right)^2+\cos^2\theta=1\\\\\dfrac{1}{4}+\cos^2\theta=1\qquad\text{subtract}\ \dfrac{1}{4}\ \text{from both sides}\\\\\cos^2\theta=\dfrac{4}{4}-\dfrac{1}{4}\\\\\cos^2\theta=\dfrac{3}{4}\to\cos\theta=\pm\sqrt{\dfrac{3}{4}}\to\cos\theta=\pm\dfrac{\sqrt3}{\sqrt4}\to\cos\theta=\pm\dfrac{\sqrt3}{2}\\\\\theta\in[0^o,\ 90^o],\ \text{therefore all functions have positive values or equal 0.}\\\\\cos\theta=\dfrac{\sqrt3}{2}

\sin2\theta=2\left(\dfrac{1}{2}\right)\left(\dfrac{\sqrt3}{2}\right)=\dfrac{\sqrt3}{2}\\\\\cos2\theta=\left(\dfrac{\sqrt3}{2}\right)^2-\left(\dfrac{1}{2}\right)^2=\dfrac{3}{4}-\dfrac{1}{4}=\dfrac{3-1}{4}=\dfrac{2}{4}=\dfrac{1}{2}

3 0
3 years ago
What is 5x^2+11x+2 factored
Alina [70]

Answer:

(x+2) (5x)

Step-by-step explanation:

the way I factor is the products of a*c added together equals b. so the products if (5*2) 10 equals 11. so 10 and 1 are the 2 products that add into 11. Now we put that into the equation. 5x^2+10x+1x+2 now take the two haves until you can't factor them any more 5x(x+2) (x+2). now take the repeated factor and outside factors to get (5x) and (x+2)

4 0
3 years ago
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