Answer:
p-value: 0.0367
Decision: Reject H₀
Step-by-step explanation:
Hello!
Hypothesis to test:
H₀:ρ₁-ρ₂=0
H₁:ρ₁-ρ₂>0
The statistic to use to test the difference between two population proportions is the approximation of Z
Z=<u> (^ρ₁-^ρ₂)-(ρ₁-ρ₂) </u> ≈N(0;1)
√ (<u>^ρ₁(1-^ρ₁))/n₁)+(^ρ₂(1-^ρ₂)/n₂))</u>
Z=<u> (0.28-0.15)-0 </u>= 1.79
√ (<u>0.28(1-0.28)/200)+(0.15(1-0.15)/300)</u>
p-value
Remember: The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis).
P(Z>1.79)= 0.0367
Conclusion:
Comparing the p-value against the significance level, you can decide to reject the null hypothesis.
I hope you have a SUPER day!
5/9* 32
= (5*32)/9
= 160/9
= (153+ 7)/9
= 153/9+ 7/9
= 17+ 7/9
= 17 7/9
The final answer is 17 7/9~
Answer:
The meal was $16.00.
Step-by-step explanation:
since the equation for finding the tip is: decimal of percent times total bill, what you want to do is isolate the bill. you do this by dividing both sides by percent and your equation is total cost = tip/percent
let's say our total equation is x.
x=3.20/0.2
x=16
Now check your work.
Answer:
can you take a better picture?
Step-by-step explanation:
Answer:
$9,812.29
Step-by-step explanation:
The amount in Jeremy's account can be computed using the compound interest formula.
__
<h3>account value</h3>
The formula for the value of an account earning compound interest at annual rate r, compounded n times per year for t years is ...
A = P(1 +r/n)^(nt)
where P is the principal invested.
__
<h3>formula application</h3>
When P=$8500, r=0.024, n=4, t=6, the formula becomes ...
A = $8500(1 +0.024/4)^(4·6) = $8500(1.006^24) ≈ $9812.29
There will be $9,812.29 in this account after 6 years.
