What’s the product? (3x-6) (2x^2-7+1)

Mathematics

2 answers:

faust18 [17]3 years ago

6 0

Answer:

Assuming you are using the zero product property, x = 2, √(3), -√(3)

Step-by-step explanation:

first I factored the (2x^2-7+1) into 2(x^2 - 3)

I also factored the (3x-6) into 3(x - 2)

Now I have the equation 6(x - 2)(x^2 - 3) = 0

I'll start with the easiest one, which is x - 2 = 0, which gives me 2

Now I solve for x^2 - 3 = 0, and I end up with two answers:

√(3) and -√(3)

So in total, x as 3 answers

Angelina_Jolie [31]3 years ago

3 0

Answer:

Step-by-step explanation:

because the carrot is wrong

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Comment on the arithmetic

Fractions are multiplied and divided in the usual way:

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Comment on fractions and parentheses

Please note that parentheses are required on any numerator or denominator that consists of anything other than a single number or variable. (The exception is the case where the numerator is a product, because a·b/c = (a·b)/c with or without the parentheses.)