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harkovskaia [24]
4 years ago
13

In a study of pain relievers , 100 people were given product A , and all but 33 experienced relief . In the same study , 50 peop

le were given product B , and all but 12 experienced relief
Mathematics
1 answer:
fenix001 [56]4 years ago
5 0

Answer:

Here we want to find the relative frequencies for both products.

for product A we have a sample of 100 people (our 100%) and all but 33 of them experienced relief.

Then, we can find the relative frequency as:

Pa = (33/100)*100% = 33%

this means that product A is not efficient in 33% of the cases.

For product B, the sample is 50 people (our 100%) and all but 12 of them experienced relief, then the relative frequency is:

Pb = (12/50)*100% = 24%.

This means that product B is not efficient in 24% of the cases.

We can see that, in percentage, the product B seems to be more efficient.

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Find the area of a rhombus with a perimeter equal to 40 and a diagonal equal to 14 cm.
krek1111 [17]

Answer:

  about 100 cm²

Step-by-step explanation:

The side length of the rhombus is 1/4 of the perimeter so is 10 cm. The length of half of the other diagonal will be the length of the leg of a right triangle with hypotenuse 10 and leg 7 (half the given diagonal).

  d= √(10² -7²) = √51

Then the area of the rhombus is the product of this and the given diagonal:

  A = (14 cm)(√51 cm) ≈ 99.98 cm²

The area of the rhombus is about 100 cm².

6 0
4 years ago
hich rectangle is an enlargement of a 5 by 6 rectangle? Rectangle A B C D Width 10 15 25 60 Length 11 18 36 60
Natalka [10]

The answer is C; 25 by 36

I did the edgenuity quiz for this so I now what it is

5 0
3 years ago
Read 2 more answers
Identify the correct HYPOTHESIS used in a hypothesis test of the following claim and sample data: Claim: "The average annual hou
lora16 [44]

Answer:

We accept H₀

Step-by-step explanation:

Population mean  μ₀ = 47500

Population standard deviation unknown

Sample size    n = 86   degree of freedom  df = 86 - 1  df = 85

Sample mean    μ = 48061

Sample standard deviation 2,351

The claim implies a two tail test with t-studend distributon

Null  Hypothesis                 H₀               μ  =  μ₀

Alternative Hypothesis      Hₐ               μ  ≠  μ₀      

Confidence Interval  mean α = 0,02     and   α/2  =  0,01

With α/2 and df = 85, from t-table we find  t(c)  critical value

t(c) = 2,3710

We compute t(s) as

t(s)  =  ( μ - μ₀ ) / s /√n

t(s)  = ( 48061 - 47500 )/ 2351/√86

t(s)  = 561 * 9,273 / 2351

t(s) = 2,212

Now we compare t(s) and t(c)

t(s) < t(c)       2,212  < 2,371

Then we are in the acceptance region. We accept H₀

5 0
3 years ago
Simplify: 4(2b + 2) – 3​
nata0808 [166]

Answer:

=8b + 5

Step-by-step explanation:

do you need an explantion

5 0
3 years ago
Read 2 more answers
Urgent
Damm [24]

The result of our calculations about the rate and time are:

  • r=d/t
  • 200000m/hr
  • 200km/hr
  • km/hr

<h3>What is rate?</h3>

Rate can be regarded as the given object with respect to time.

falcon flies= 800,000 meters

t= 4 hours

We were given the  formula as (d = rt)

d= distance

r = rate

t = time

We can make our calculations as:

part a:

r=d/t

part b:

falcon's rate in meters per hour = 800,000 meters / 4 hours = 200000m/hr

part c:

falcon's rate in kilometers per hour=(200000m/hr *(1/1000)=200km/hr

part d:

km/hr

Learn more about rate at:

brainly.com/question/8728504

#SPJ1

4 0
2 years ago
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