Each compound will be neutral
Find the [OH-] in the solution. The pH is 9.5, so the pOH is 14 - 9.5 = 4.5.
[OH-] = 10^-4.5 M
Now use the dilution equation to find the new [OH-] after the volume is reduced from 150 mL to 50 mL:
M1V1 = M2V2
M1 = 10^-4.5 M
V1 = 150 mL
M2 = ?
V2 = 50 mL
(10^-4.5)(150) = M2(50)
M2 = 9.5 x 10^-5 M ≈ 1 • 10^-4 (We can only use one sig fig, because the pH was given to one decimal place.)
Now use this [OH-] to find pOH:
pOH = -log(1 x 10^-4) = 4.0
14 - pOH = pH, so the expected pH for the new solution is 10.
This statement is TRUE.
The ionization energy presents the amount of energy required for the release of the valence electron, the electron farthest from the core. The smaller the amount of energy needed for the release is, the lower the ionization energy is.
Therefore, the atoms with low ionization require little energy to release their valence electrons and they do it easier that the atoms with high ionization energy.
Sodium has an atomic number 11, it means there are 11 electrons in sodium atom and has a net charge zero what when it combines with chlorine it loses one electron and get charge of +1. when and atom loses an electron it gets positive charge and when atom gains electron it gets negative charge. chlorine makes an anion and sodium makes cation and they are oppositely charged so they react with each other.