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LekaFEV [45]
3 years ago
8

What is the molar mass of (NH), CO? 138g 788 968 1448

Chemistry
1 answer:
aleksandr82 [10.1K]3 years ago
7 0

Answer:

The molar mass of (NH_{4})_{2}CO_{3} is 96.8 g/mol

Explanation:

The given molecular formula - (NH_{4})_{2}CO_{3}

Individual molar masses of each element in the compound is as follows.

Molar mass of nitrogen - 14.01 g/mol

Molar mass of of hydrogen = 1.008g/mol

Molar mass of carbon = 12.01 g/mol

Molar mass of oxygen =16.00 g/mol

Molar mass of (NH_{4})_{2}CO_{3} is

2\times[1(14.01)+4(1.008)]+1(12.01)+3(16.00)= 96.8g/mol

Therefore,The molar mass of (NH_{4})_{2}CO_{3} is 96.8 g/mol

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How many carbon atoms are there in a diamond (pure carbon) with a mass of 55 mg ?
kari74 [83]
1 mol of Carbon = 12 grams.
x mol of Carbon = 55 grams

12*x = 1 * 55
x = 55/12
x = 4.583333 mols of carbon

1 mol of anything is 6.02 * 10^23 atoms
4.58333333 mol = x

1/4.5833333 = 6.02 * 10^23/x
x = 4.58333* 6.02*10^23
x = 2.7591 * 10^23 Carbon atoms
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3 years ago
Millimeters, centimeters, meters, kilometers, Inches,<br> feet, and miles are all examples of
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Answer:

Distance, some kind of distance or length.

Explanation:

 

4 0
2 years ago
Barium-131 is used in the detection of bone tumors. The half-life of barium-131 is approximately 12 days. How long will it take
Evgesh-ka [11]

Barium-131's radiation level won't reach 1/4 of its initial level for 24 hours.

ln[A] t = -kt + ln[A] 0 is the integrated rate rule for the first-order reaction A's products.

A straight line is produced when the natural log of [A] is plotted as a function of time since this equation has the form y = mx + b.

How is the length of a half-life determined?

The amount of time needed for the reactant concentration to drop to half its initial value is known as the half-life of a reaction. A first-order reaction's half-life is a constant that is correlated with its rate constant:

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5 0
1 year ago
Find the empirical formula of the following compounds:
Aneli [31]

The empirical formula of the following compounds 0.903 g of phosphorus combined with 6.99 g of bromine.

<h3>What is empirical formula?</h3>

The simplest whole number ratio of atoms in a compound is the empirical formula of a chemical compound in chemistry. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S2O2, are two straightforward examples of this idea. As a result, both the sulfur and oxygen compounds sulfur monoxide and disulfur dioxide have the same empirical formula.

<h3>How to find the empirical formula?</h3>

Convert the given masses of phosphorus and bromine into moles by multiplying the reciprocal of their molar masses. The molar masses of phosphorus and bromine are 30.97 and 79.90 g/mol, respectively.

Moles phosphorus = 0.903 g phosphorus \frac{mol phosphorus}{ 30.97 g phosphorus}= 0.0293 mol

Moles bromine 6.99 g bromine\frac{mol bromine}{79.90 g bromine}=0.0875 mol

The preliminary formula for compound is P0.0293Bro.0875. Divide all the subscripts by the subscript with the smallest value which is 0.0293. The empirical formula is P1.00Br2.99 ≈ P₁Br3 or PBr3

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8 0
1 year ago
What kinds of substances besides water can be involved in hydrogen bonding?
MrMuchimi
<span>Kind of substance besides water:
The best example of hydrogen bonding excluding water is DNA. The two strands of polymers are connected by hydrogen bonds between the nucleotide bases</span>.
7 0
3 years ago
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