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inn [45]
3 years ago
13

When you drop a 0.44 kg apple, Earth exerts

Physics
1 answer:
OleMash [197]3 years ago
3 0

Answer:

7.2×10⁻²⁵ m/s²

Explanation:

F = ma

(0.44 kg) (9.8 m/s²) = (5.98×10²⁴ kg) a

a = 7.2×10⁻²⁵ m/s²

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And object has traveled 200 m in 20 seconds what is its average speed
BabaBlast [244]
It is going 10m speed
8 0
3 years ago
Technician A says that the crankshaft determines the stroke of an engine. Technician B says that the length of the connecting ro
Rudik [331]

Answer:

Technician A is correct.

Explanation:

Stroke of the engine means how far is the piston moves during the cycle.It is determined by the crank of the crank shaft. Engine displacement volume  is calculated by multiplying length of the stroke to the piston displacement area.

                          If there are more than one cylinder in the engine, than in that case this number in multiplied by the number of the cylinders inside the engine.

Therefore technician A is correct.

7 0
4 years ago
A hockey puck slides off the edge of a horizontal platform with an initial velocity of 28.0 m/shorizontally in a city where the
kozerog [31]

Answer:

θ = 12.60°

Explanation:

In order to calculate the angle below the horizontal for the velocity of the hockey puck, you need to calculate both x and y component of the velocity of the puck, and also you need to use the following formula:

\theta=tan^{-1}(\frac{v_y}{v_x})       (1)

θ: angle below he horizontal

vy: y component of the velocity just after the puck hits the ground

vx: x component of the velocity

The x component of the velocity is constant in the complete trajectory and is calculated by using the following formula:

v_x=v_o

vo: initial velocity = 28.0 m/s

The y component is calculated with the following equation:

v_y^2=v_{oy}^2+2gy         (2)

voy: vertical component of the initial velocity = 0m/s

g: gravitational acceleration = 9.8 m/s^2

y: height

You solve the equation (2) for vy and replace the values of the parameters:

v_y=\sqrt{2gy}=\sqrt{2(9.8m/s^2)(2.00m)}=6.26\frac{m}{s}

Finally, you use the equation (1) to find the angle:

\theta=tan^{-1}(\frac{6.26m/s}{28.0m/s})=12.60\°

The angle below the horizontal is 12.60°

7 0
3 years ago
What is the magnitude of a point charge in coulombs whose electric field 58 cm away has the magnitude 2.8 N/C?
Yuliya22 [10]

Answer:

q = 1.05 × 10^-10 C

Explanation:

E = 2.8 N/C

r = 58cm = 0.58m

k = 9×10^9

q = ?

E = f/q

E = kq/r²

q = E*r²/k

q = (2.8×0.58²)÷9×10^9

q = 1.05 × 10^-10 C

8 0
3 years ago
How does a longshore current affect a beach?
77julia77 [94]
Longshore currents are affected by the velocity and angle of a wave. When a wave breaks at a more acute (steep) angle on a beach, encounters a steeper beach slope, or is very high, longshore currents increase in velocity. ... This process, known as “longshore drift,” can cause significant beach erosion.
8 0
3 years ago
Read 2 more answers
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