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3 years ago

How does a longshore current affect a beach?

2 answers:

8 0

Longshore currents are affected by the velocity and angle of a wave. When a wave breaks at a more acute (steep) angle on a beach, encounters a steeper beach slope, or is very high, longshore currents increase in velocity. ... This process, known as “longshore drift,” can cause significant beach erosion.

raketka [301]3 years ago

3 0

Answer:

"Longshore currents are affected by the velocity and angle of a wave. When a wave breaks at a more acute (steep) angle on a beach, encounters a steeper beach slope, or is very high, longshore currents increase in velocity. ... This process, known as “longshore drift,” can cause significant beach erosion."

Credits to ocean service

Explanation:

Hope this helps

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A non-reflective coating that has a thickness of 198 nm (n = 1.45) is deposited on top of a substrate of glass (n = 1.50). What

spin [16.1K]

Answer:

The wavelength is $\lambda_ 1 = 574.2 nm$

Explanation:

From the question we are told that

The thickness is $t = 198 nm = 198 *10^{-9 }\ m$

The refractive index of the non-reflective coating is $n_m = 1.45$

The refractive index of glass is $n_g = 1.50$

Generally the condition for destructive interference is mathematically represented as

$2 * n_m * t * cos (\theta) = n * \lambda$

Where $\thata$ $\theta$ is the angle of refraction which is 0° when the light is strongly transmitted

and n is the order maximum interference

$\lambda = \frac{2 * n * t * cos (\theta )}{n}$

at the point n = 1

$\lambda _1 = \frac{2 * 1.45 * 198*10^{-9} * cos (0 )}{1}$

$\lambda_1 = 574.2 *10^{-9}$

$\lambda_1 = 574.2 nm$

at n =2

$\lambda _2 = \frac{\lambda _1 }{2}$

$\lambda _2 = \frac{574.2*10^{-9} }{2}$

$\lambda _2 = 2.87 1 *10^{-9} \ m$

$\lambda _2 = 287. 1 nm$

Now we know that the wavelength range of visible light is between

$390 \ nm \to 700 \ nm$

So the wavelength of visible light that is been transmitted is

$\lambda_ 1 = 574.2 nm$

6 0

4 years ago

Excellent human jumpers can leap straight up to a

Shkiper50 [21]

The speed that the person needs to leave the ground will be 4.32m/s

From the question given,

Height = 95cm

Since the person leave the ground v = 0m/s

acceleration due to gravity g = 9.8m/s²

Using the equation of motion

v² = u² + 2as

a = -g (upward motion)

s = h (distance changes to height)

The equation will become:

0² = u² - 2gh

0² = u² - 2(9.8)(0.95)

u² = 18.62

u = √18.62

u = 4.32

Hence the speed that the person needs to leave the ground will be 4.32m/s

Learn more here: brainly.com/question/20352766

8 0

2 years ago

Use the term chemical change in a complete sentence

Arada [10]

Answer:

A paper being burned is a chemical change.

3 0

3 years ago

A man stands at the edge of a cliff and throws a rock downward with A speed of 12.0 m s . Sometimes later it strikes the ground

kvasek [131]

B) 48.0 m/s

We can actually start to solve the problem from B for simplicity.

The motion of the rock is a uniformly accelerated motion (free fall), so we can find the final speed using the following suvat equation

$v^2 -u^2 = 2as$

where

$v$ is the final velocity

$u = 12.0$ is the initial velocity (positive since we take downward as positive direction)

$a=g=9.8 m/s^2$ is the acceleration of gravity

s = 110 m is the vertical displacement

Solving for v, we find the final velocity (and so, the speed of the rock at impact):

$v = \sqrt{u^2+2as}=\sqrt{12^2+2(9.8)(110)}=48.0 m/s$

A) 3.67 s

Now we can find the time of flight of the rock by using the following suvat equation

$v=u+at$

where

$v = 48.0$ is the final velocity at the moment of impact

$u = 12.0$ is the initial velocity

$a=g=9.8 m/s^2$ is the acceleration of gravity

t is the time it takes for the rock to reach the ground

And solving for t, we find

$t=\frac{v-u}{a}=\frac{48.0-12.0}{9.8}=3.67 s$

6 0

3 years ago

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crimeas [40]

Answer:

parallel circuit is a kind of circuits in which all components are connected between the same two sets of electrically common points, creating multiple paths for the current to flow from one end of the battery to the other:

8 0

3 years ago

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