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Lera25 [3.4K]
3 years ago
15

And object has traveled 200 m in 20 seconds what is its average speed

Physics
1 answer:
BabaBlast [244]3 years ago
8 0
It is going 10m speed
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Four solid plastic cylinders all have radius 2.55 cm and length 5.70 cm. Find the charge of each cylinder given the following ad
vazorg [7]

Answer:3

Explanation:idk

5 0
3 years ago
When the hydraulic conductivity Ks = 10 mm/hr; effective matrix potential Ns = 20 mm, and rainfall intensity I = 30 mm/hr , dete
Maslowich

Answer:

t =  0.75 \ hr  =  0.75 *60  =  45 \ minutes

Explanation:

From the question we are told that

   The  hydraulic conductivity is  Ks =  10\ mm/hr

    The  effective matrix potential Ns  =  20 \ mm

    The  intensity of  rainfall is  I  =  30 \ mm/hr

    The runoff rate R =  15 \  mm/hr

Generally the run off rate is mathematically represented as  

      R = (I - Ks) t

Here t is the amount of runoff generated

=>   15 = (30 - 10) t

=>  t  =  0.75 \ hr

converting to minutes

    t =  0.75 \ hr  =  0.75 *60  =  45 \ minutes

3 0
3 years ago
What do you spiral and elliptical galaxies have in common
malfutka [58]
They have a uniform luminosity and are similar to the bulge in a spiral galaxy, but with no disk. The stars are old and there is no gas present. Ellipticals are usually found in the high density field, at the centre of clusters.
3 0
3 years ago
Please please need help on this one
Advocard [28]
I’m guessing it’s the last one, trough
4 0
3 years ago
Suppose you walk 21.5 m straight east and then 12.5 m straight north. How far are you from your starting point (in m)
stira [4]

Answer:

24.9 m

Explanation:

A triangle is a polygon with three sides and three angles. There are different types of triangles such as the equilateral triangle, isosceles triangle, scalene triangle, right angled triangle.

You walk 21.5 m straight east and then 12.5 m straight north. This forms a right angled triangle with a horizontal distance of 21.5 m, a vertical distance of 12.5 m and the hypotenuse is the distance between the ending and starting point. Let x represent the distance between the ending and starting point. Therefore using Pythagoras theorem:

x² = 21.5² + 12.5²

x² = 462.25 + 156.25

x² = 618.5

Taking square root of both sides:

√x² = √618.5

x = √618.5

x = 24.9 m = distance between the ending and starting point.

4 0
3 years ago
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