All categories

3 years ago

Jason and Kyle both choose a number from 1 to 10 at random. What is the probability that both numbers are odd?

Mathematics

1 answer:

Bezzdna [24]3 years ago

5 0

Half of the numbers between 1 to 10 are odd, 1,3,5,7,9.
So the probability is 1/2.
Hope this helps.

You might be interested in

Question

balandron [24]

Answer:

The approximate percentage of SAT scores that are less than 865 is 16%.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean of 1060, standard deviation of 195.

Empirical Rule to estimate the approximate percentage of SAT scores that are less than 865.

865 = 1060 - 195

So 865 is one standard deviation below the mean.

Approximately 68% of the measures are within 1 standard deviation of the mean, so approximately 100 - 68 = 32% are more than 1 standard deviation from the mean. The normal distribution is symmetric, which means that approximately 32/2 = 16% are more than 1 standard deviation below the mean and approximately 16% are more than 1 standard deviation above the mean. So

The approximate percentage of SAT scores that are less than 865 is 16%.

8 0

2 years ago

Write an algebraic expression for the given quantity. Let X represent the unknown value one fourth of the sum of a number and ei

Leviafan [203]

I think that (1/4)x+8 would be your algebraic expression.

4 0

3 years ago

2.The number of tickets sold to a play for each showing is 78, 84, 87, 80, 91, 95, and 80.

Luden [163]

Answer:

$Min =78$

The maximum is :

$Max = 95$

Now we can calculate the median since the sample size os n =7 the median would be the middle value at the position 4 from the dataset ordered and we got:

$Median =84$

Now we can find the quartile 1 we analyze the first 4 values 78, 80,80, 84 and the first quartile would be:

$Q_1= \frac{80+80}{2}= 80$

Now we can find the quartile 3 we analyze the last 4 values 84,87, 91, 95 and the third quartile would be:

$Q_3= \frac{87+91}{2}=89$

And finally the 5 number summary would be:

$Min = 78, Q_1 = 80, Median=84, Q_3 = 89, Max=96$

Step-by-step explanation:

We have the following data given:

78, 84, 87, 80, 91, 95, and 80.

The first step is order the dataset on increasing way and we got:

78, 80,80, 84,87, 91, 95

We can begin finding the minimum value and for this case is:

$Min =78$

The maximum is :

$Max = 95$

Now we can calculate the median since the sample size os n =7 the median would be the middle value at the position 4 from the dataset ordered and we got:

$Median =84$

Now we can find the quartile 1 we analyze the first 4 values 78, 80,80, 84 and the first quartile would be:

$Q_1= \frac{80+80}{2}= 80$

Now we can find the quartile 3 we analyze the last 4 values 84,87, 91, 95 and the third quartile would be:

$Q_3= \frac{87+91}{2}=89$

And finally the 5 number summary would be:

$Min = 78, Q_1 = 80, Median=84, Q_3 = 89, Max=96$

5 0

3 years ago

Evaluate the following expression when x = 6 and y = 2:

Liula [17]

Answer:

11/2

Step-by-step explanation:

$\frac{ {x}^{2} + {y}^{3} }{2 + x} \\$

when,

$x = 6 \\ y = 2$

Now substitute the value we get,

$\frac{ {6}^{2} + {2}^{3} }{2 + 6} \\ \\ = \frac{36 + 8}{8} \\ \\ = \frac{44}{8} \\ \\ = \frac{11}{2}$

5 0

3 years ago

Insert grouping symbols in 5 x 2 + 8 - 4 - 2 so that its value is 15

Arlecino [84]

5×2+8-4+1=15
cause
5×2=10
10+8=18
18-4=14
14+1=15

5 0

3 years ago