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3 years ago

7

Evaluate the expression for the given values. 8x+2yz , where x=12 , y = 4, and z = 2 Enter your answer in the box. need this ASA

P!!!!!!

2 answers:

Alisiya [41]3 years ago

5 0

Answer:

6?

Step-by-step explanation:

FromTheMoon [43]3 years ago

3 0

112 is the answer I think

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The graphs of f(x)=2x+4 and g(x)=10−4x intersect at (1,6) . What is the solution of the equation 2x+4=10−4x ? Enter your

nordsb [41]

X = 1, since they intersect at (1,6) and are thus equal at that point

8 0

3 years ago

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How can you show that two objects are proportional with a table?

vredina [299]

So this is our table:

-----------------
x-values | a b c d e f |
-----------------
y-values | g h i j k l |
-----------------

You can know that the values in the table are proportional if:

$\frac{a}{g}=\frac{b}{h} =\frac{c}{i}=\frac{d}{j}=\frac{e}{k}=\frac{f}{l}$

Hope that helps :)

5 0

3 years ago

WHAT IS THE ANSWER FOR THIS?!? I WILL MARK BRAINLIEST!!!

Dimas [21]

1. it’s saying 2-6 which is -4

2. it’s saying -6-5 which is -11

6 0

3 years ago

If y varies inversely with the square of r, what is the constant of proportionality when y - 10 and 1 = 5?

Anvisha [2.4K]

<em><u>Question:</u></em>

If y varies inversely with the square of r, what is the constant of proportionality when y =10 and r = 5?

<em><u>Answer:</u></em>

The constant of proportionality is 250

<em><u>Solution:</u></em>

Given that,

y varies inversely with the square of r

Which means,

$y \propto \frac{1}{r^2}\\\\y = k \times \frac{1}{r^2}$

Where, "k" is constant of proportionality

Subtitute y = 10 and r = 5

$10 = k \times \frac{1}{5^2}\\\\10 = k \times \frac{1}{25}\\\\k = 10 \times 25\\\\k = 250$

Thus the constant of proportionality is 250

6 0

3 years ago

The box plots below show the distribution of salaries, in thousands, among employees of two small companies.

Shtirlitz [24]

Answer:

Mean and IQR

Step-by-step explanation:

The measure of centre gives the central or the measure which gives the best mid term of a distribution. Based in the details of the box plot, the median is the value which divides the box in the box plot.

For company A:

Range = 25 to 80 with a median value at 30 ; this means the median does not give a good centre measure of the distribution ad it is very close to the minimum value. This goes for the Company B plot too; with values ranging from (35 to 90) and the median designated at 40.

Hence, the mean will be the best measure of centre rather Than the median in this case.

For the variability, the interquartile range would best suit the distribution. With the lower quartile and upper quartile both having reasonable width to the minimum and maximum value of the distribution.

7 0

3 years ago

Read 2 more answers