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3 years ago

A tennis ball is dropped from 1.16 m above the

Physics

1 answer:

sweet-ann [11.9K]3 years ago

6 0

Answer:

Vf = 4.77 m/s

Explanation:

During the downward motion we can easily find the final velocity or the velocity with which the ball hits the ground, by using third equation of motion. The third equation of motion is given as follows:

2gh = Vf² - Vi²

where,

g = acceleration due to gravity = 9.8 m/s²

h = height = 1.16 m

Vf = Final Velocity of Ball = ?

Vi = Initial Velocity of Ball = 0 m/s (Since, ball was initially at rest)

Therefore, using these values in the equation, we get:

(2)(9.8 m/s²)(1.16 m) = Vf² - (0 m/s)²

Vf = √(22.736 m²/s²)

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1 year ago

If the voltage of a circuit of 1 bulb has a resistance of 45 V and produces

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3 years ago

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3 years ago

A NASCAR driver weighing 75 kg enters a corner with a radius of 155 meters. If his acceleration is 100 m/s2. What is tangential

Ymorist [56]

The tangential velocity of the car is 124.5 m/s

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3 0

3 years ago

1. A baseball that has been thrown is travelling at 40m/s. If

nignag [31]

Answer:

See explanations below

Explanation:

1) KE = 1/2mv²

mass m = 0.142kg

v = 40m/s

KE = 1/2 * 0.142 * 40^2

KE = 1/2 * 0.142 * 1600

KE = 800*0.142

KE = 113.6Joules

2) KE = 1/mv^2

KE = 196

mass m = ?

velocity v = 52m/s

Substitute

196 = 1/2*m*52²

196 = 1352m

m = 196/1352

m = 0.145kg

Hence the mass of the baseball is 0.145kg

3) KE = 1/2mV^2

288 = 1/2 * 4v²

288 = 2v²\

v² = 288/2

v² = 144

v = 12m/s

The velocity of the shotput is 12m/s

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3 years ago