All categories

3 years ago

How long will it take to fall 50 m?

Physics

1 answer:

Ad libitum [116K]3 years ago

6 0

Answer:

down below

Explanation:

Since we aren't the given the time, lets say that an object to 25 seconds to fall 50 meters. We can use the formula [ s = d/t ] to solve.

s = 50/25

s = 2

Therefore, the object was falling at a rate of 2 meters per second.

Best of Luck!

You might be interested in

AP Physics I, shouldn't be too hard.

Nana76 [90]

Answer:

The correct option is;

D. The kinetic energy decreases by 3·m₀·v₀²

Explanation:

The given parameters are;

The mass of object X = m₀

The initial velocity of object X = v₀

The mass of object Y = 2·m₀

The initial velocity of object Y = -2·v₀

By conservation of linear momentum, we have;

The total initial momentum = The total final momentum

Therefore, we have;

The total initial momentum = m₀·v₀ - 2·m₀·2·v₀ = The total final momentum

∴ The total final momentum = -3·m₀·v₀

The total mass of the two object after sticking together = 2·m₀ + m₀ = 3·m₀

Therefore, the velocity of the two objects after collision = (The total final momentum)/(Total mass) = -3·m₀·v₀/(3·m₀) = -v₀

The kinetic energy = 1/2 × Mass × (Velocity)²

Therefore, the kinetic energy after collision = 1/2 × (3·m₀) × v₀² = 3·m₀·v₀²/2

The kinetic energy before collision = 1/2 × m₀ × v₀² + 1/2 × (2·m₀) × (2·v₀)² = (1/2 + 4) × (m₀·v₀²)

∴ The kinetic energy before collision = 9·(m₀·v₀²)/2

The change in kinetic energy = The kinetic energy after collision - The kinetic energy before collision = 3·m₀·v₀²/2 - 9·(m₀·v₀²)/2 = -3·m₀·v₀²

Therefore, the kinetic energy decreases by 3·m₀·v₀².

5 0

3 years ago

a wrench weighs 5.24 newtons on earth. when it is taken to the Moon, where g =1.16 m/s2 how much does it weigh?

Andrew [12]

“Weight of the wrench” on “the moon” is “6.07 kg”.

<u>Explanation</u>:

Weight of the wrench is 5.24 N

Weight of the wrench in kilograms = W × g

Taken “g” on the moon is $1.16 \mathrm{m} / \mathrm{s}^{2}$

$=5.24 \mathrm{N} \times 9.81 \mathrm{m} / \mathrm{s}^{2}=51.352 \mathrm{kg}$

Weight of the wrench in kilograms is 51.352 kg.

Formula to calculate weight of the object on the moon is

$\frac{\text {weight of the object on earth}}{9.81 \mathrm{m} / \mathrm{s}^{2}} \times 1.16 \mathrm{m} / \mathrm{s}^{2}$

Substitute the values given,

$=\frac{51.352 \mathrm{kg}}{9.81 \mathrm{m} / \mathrm{s}^{2}} \times 1.16 \mathrm{m} / \mathrm{s}^{2}$

$=5.234 \times 1.16$

= 6.07 kg

Therefore, weight of the wrench on the moon is 6.07 kg.

6 0

3 years ago

a measuring cylinder contains 30cm3 of a liquid some more of the liquid is added until the liquid level reaches the 50cm3 mark t

S_A_V [24]

Answer:

1.5g/cm³

Explanation:

Given parameters:

Initial volume of the liquid = 30cm³

Final volume of the liquid = 50cm³

Mass of the liquid = 30g

Unknown:

Density of the liquid = ?

Solution:

Density is the mass per unit volume of a substance.

Density = $\frac{mass}{volume}$

volume of the liquid = final volume - initial volume = 50cm³ - 30cm³

volume of the liquid = 20cm³

Density = $\frac{30}{20}$ = 1.5g/cm³

6 0

3 years ago

Show that linear S.H.M is projection of a U.C.M along any of its diameter

BigorU [14]

It shows that acceleration of particle M is directly proportional to its displacement and its direction is opposite to that of displament. Thus particle M performs simple harmonic motion but M is projection of particle performing U.C.M. hence S.H.M. is projection of U.C.M. along a diameter, of circle.

4 0

3 years ago

You volunteer to travel to a newly discovered planet about 30 light years from earth. At what speed do you need to travel to rea

Mars2501 [29]

6 light years speed

8 0

3 years ago

Read 2 more answers