We have the function:
()=−2(−3)^4+1
We need to go from this equation to the parent function x^4. To do that, we first do a vertical translation of 1 unit below. That is:
Vertical translation: f(x) - 1
= −2(−3)^4
Now, we make a horizontal shift of 3 units to the left, replacing x by x + 3:
f(x + 3) + 1 = −2()^4
Horizontal shift: f(x + 3) - 1
= −2x^4
We can make a horizontal expansion if we multiply this function by 1/2:
Horizontal expansion: ( f(x + 3) - 1 ) / 2
= -x^4
Finally, we make a reflection around the x-axis by multiplying this result by -1:
x-axis reflection: -( f(x + 3) - 1 ) / 2
= x^4
we know that
For the function shown on the graph
The domain is the interval--------> (-∞,0]

All real numbers less than or equal to zero
The range is the interval--------> [0,∞)

All real numbers greater than or equal to zero
so
Statements
<u>case A)</u> The range of the graph is all real numbers less than or equal to 
The statement is False
Because the range is all numbers greater than or equal to zero
<u>case B)</u> The domain of the graph is all real numbers less than or equal to 
The statement is True
See the procedure
<u>case C)</u> The domain and range of the graph are the same
The statement is False
Because the domain is all real numbers less than or equal to zero and the range is is all numbers greater than or equal to zero
<u>case D)</u> The range of the graph is all real numbers
The statement is False
Because the range is all numbers greater than or equal to zero
therefore
<u>the answer is</u>
The domain of the graph is all real numbers less than or equal to 
If the question is, "What is the scale factor." That would be a scale (factor) of 2.
<u>Answer:</u>
The Kinetic energy of the 110 kg linebacker is 1375 J
<u>Solution:</u>
The kinetic energy of an object is the energy produced by its velocity. Kinetic energy of an object is directly proportional to the mass and the square of the its velocity.
Therefore, the formula for kinetic energy is

Here, The linebacker’s mass m = 110 kg
The linebacker’s velocity v = 5 m/s
So by substituting the values,
The kinetic energy of linebacker is
