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NARA [144]
3 years ago
11

Rick says to find 2 x 5, he can use counting by 5's: 5, 10, 15, 20, 25. Explain what he did wrong.

Mathematics
2 answers:
Masja [62]3 years ago
8 0
2x5 can be changed to 5 plus 5
MAXImum [283]3 years ago
7 0
Technically what he did could work, because 2 * 5 can be changed to 5 + 5 which you can get to by counting 5's.
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Given the linear system:
azamat

Answer:

y=x+1/2z+-1/2

Step-by-step explanation:

Let's solve for y.

2x−2y+z=1

Step 1: Add -2x to both sides.

2x−2y+z+−2x=1+−2x

−2y+z=−2x+1

Step 2: Add -z to both sides.

−2y+z+−z=−2x+1+−z

−2y=−2x−z+1

Step 3: Divide both sides by -2.

-2y/-2 = -2-z+1/-2

y=x +1/2z+-1/2

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3 years ago
Yolonda withdrew 60 dollars from her checking account.Write a signed number to represent this change in her account.
JulsSmile [24]

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$ 60.00

Step-by-step explanation:

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2 years ago
What’s the Pythagorean therorimm
Lera25 [3.4K]

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38.29 i think

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
the strength of students in a school when increased by 8% becomes 2160. find the original strength of students in the school.
Leni [432]

Answer:

1987.2

Step-by-step explanation:

We can write a proportion to find the total amount in the choir using the information given. A proportion is two equivalent ratios set equal to each other. Since we know the strength of students increased by 8% to 2160 then the original was 92%.

\frac{92}{100}=\frac{y}{2160}

We will cross multiply the numerator of one ratio with denominator of the other. And then solve for y.

92(2160)=100(y)

198720=100y

y=1987.2

There are 1987.2 as the original strength of students.


6 0
3 years ago
The shape below contains a rectangle and four semi-circles. What is the perimeter of the shape above? What is the area of the sh
Colt1911 [192]

Answer:

Step-by-step explanation:

lets find out the perimeter P

P rectangle= 2*L+2*W=(2*5)+(2*13)=10+26=36

P small semi-circle ( we have 2), where the d=5, r=2.5

Circumference small circle=2*3.14*r= 2*3.14*2.5=15.70

P 2 small circles=15.70*2=31.40

but we need just half of this, because we have semicircles=15.70

Circumference big semicircle (we have 2), where d=13, r=6.5

C big circle=2*3.14*6.5=40.82

Ps big circle=2*40.82=81.64

we need half of this also, so is 40.82

P total figure=36+15.70+40.82=92.52

Area rectangle=5*13=65

Area small circle, basically the 2 semicircle = 1 circle

Area=3.14*r^2=3.14*2.5^2=19.63

Area big circle=3.14*6.5^2=132.73

Area total figure=65+19.63+132.73=217.36

5 0
3 years ago
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