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2 years ago

1. The curve y = (x - 1)(x – 5) cuts the x-axis at A and B and the y-axis at C.

1 answer:

3 0

So the first two questions are asking for points of intercept. a is asking where the function crosses the x, in this case it is where y=0. So your x intercept is at x= 1,5. Then to find the y intercept it is where x=0, so just substitute 0 for x. Then you get your y intercept as y=5. Because your coefficient for the quadratic function is positive your function has a minimum since it opens upward. I’m not sure what is means by C coordinate, but your vertex is at (3,-4) and lime of symmetry is at x=3.

X intercepts: (1,0) and (5,0)
Y intercept: (0,5)

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3 years ago

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What is <br>34<br>8<br>fraction whole number, or mixed number

bogdanovich [222]

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2 years ago

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PLZ HELP WORTH A LOT OF POINTS AND I HAVE 10 MINUTES!!!!

Lina20 [59]

Answer:

The area after 9 years will be 1,234 km^2

Step-by-step explanation:

In this question, we are tasked with calculating what the area of a certain forest that decreases at a certain percentage would be after some years.

To answer this question, we shall be using an exponential approximation.

Now, to use this exponential approximation, we shall be needing a supporting exponential mathematical equation.

This can be written as;

A = I(1-r)^t

where A is the new area we are looking for

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t is time which is 9 years according to the question

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A = 1700(1-0.035)^9

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A = 1,233.66

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2 years ago

Find the area of the surface. The part of the surface z = xy that lies within the cylinder x2 + y2 = 36.

rewona [7]

Answer:

Step-by-step explanation:

From the given information:

The domain D of integration in polar coordinates can be represented by:

D = {(r,θ)| 0 ≤ r ≤ 6, 0 ≤ θ ≤ 2π) &;

The partial derivates for z = xy can be expressed as:

$y =\dfrac{\partial z}{\partial x} , x = \dfrac{\partial z}{\partial y}$

Thus, the area of the surface is as follows:

$\iint_D \sqrt{(\dfrac{\partial z}{\partial x})^2+ (\dfrac{\partial z}{\partial y})^2 +1 }\ dA = \iint_D \sqrt{(y)^2+(x)^2+1 } \ dA$

$= \iint_D \sqrt{x^2 +y^2 +1 } \ dA$

$= \int^{2 \pi}_{0} \int^{6}_{0} \ r \sqrt{r^2 +1 } \ dr \ d \theta$

$=2 \pi \int^{6}_{0} \ r \sqrt{r^2 +1 } \ dr$

$= 2 \pi \begin {bmatrix} \dfrac{1}{3}(r^2 +1) ^{^\dfrac{3}{2}} \end {bmatrix}^6_0$

$= 2 \pi \times \dfrac{1}{3} \Bigg [ (37)^{3/2} - 1 \Bigg]$

$= \dfrac{2 \pi}{3} \Bigg [37 \sqrt{37} -1 \Bigg ]$

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2 years ago

Find the distance between the points (4,-2) and (0,10)

vagabundo [1.1K]

We can solve this problem by using the distance formula. The distance formula is: $\sqrt{(x_{1}-x)^{2} + (y_{1} - y)^{2}}$ We can now put in values and solve.

$\sqrt{(4-0)^{2} + (-2-10)^{2}}$

$\sqrt{16 + 144}$

$\sqrt{160}$

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3 years ago