The correct answer is the 2nd choice because -1/6 is closer to 0 and the surface of the pool would be considered 0. -4/6 is farther away from 0 so it is less.
Ok so A is the same as the square root of 4b+c but all of the numbers and the answer have to be prime numbers
Answer:
The Equation which shows the equality is 53 = 2 h + 5 ,
The age of Sunny's house is 24 years old
Step-by-step explanation:
Given as ;
The age of the house of Chen's is 53 years old
Let the age of of the house of sunny = h years old
So, according to question
Chen's house age is 5 years more than twice the age of sunny's house
I.e Chen's house age = 2 × sunny's house age + 5
Or, 53 = 2 × h + 5
or, 2 × h = 53 - 5
so . 2 × h = 48
∴ h = 
= 24 years
Hence The Equation which shows the equality is 53 = 2 h + 5 , And The age of Sunny's house is 24 years old . Answer
The vertex of this parabola is at (3,-2). When the x-value is 4, the y-value is 3: (4,3) is a point on the parabola. Let's use the standard equation of a parabola in vertex form:
y-k = a(x-h)^2, where (h,k) is the vertex (here (3,-2)) and (x,y): (4,3) is another point on the parabola. Since (3,-2) is the lowest point of the parabola, and (4,3) is thus higher up, we know that the parabola opens up.
Substituting the given info into the equation y-k = a(x-h)^2, we get:
3-[-2] = a(4-3)^2, or 5 = a(1)^2. Thus, a = 5, and the equation of the parabola is
y+2 = 5(x-3)^2 The coefficient of the x^2 term is thus 5.
The probability of one head and one tail is 2/3.
<u>Step-by-step explanation</u>:
- The possibilities for flipping two fair coins are {T,T}, {H,H}, {H,T}, {T,H}
- Given the case that at least one coin lands on a head, So the total possibilities are {H,H}, {H,T}, {T,H} = 3 possibilities
- Required event is 1 head and 1 tail= {H,T}, {T,H} = 2 possibilities
To calculate the probability of one head and one tail,
Probability = required events / Total events
Probability = 2/3
