Answer:
The value to the given expression is 8
Therefore ![\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7B%2810%5E4%29%285%5E2%29%7D%7B%2810%5E3%29%285%5E3%29%7D%5Cright%5D%5E3%3D8)
Step-by-step explanation:
Given expression is (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed
Given expression can be written as below
![\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7B%2810%5E4%29%285%5E2%29%7D%7B%2810%5E3%29%285%5E3%29%7D%5Cright%5D%5E3)
To find the value of the given expression:
![\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=\frac{((10^4)(5^2))^3}{((10^3)(5^3))^3}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7B%2810%5E4%29%285%5E2%29%7D%7B%2810%5E3%29%285%5E3%29%7D%5Cright%5D%5E3%3D%5Cfrac%7B%28%2810%5E4%29%285%5E2%29%29%5E3%7D%7B%28%2810%5E3%29%285%5E3%29%29%5E3%7D)
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Therefore
Therefore the value to the given expression is 8
Area of a circle= πr²
Data:
diameter=11 in
ratius=diameter/2=11 in/2=5.5 in
Area of this circular plate=π(5.5 in)²=30.25π in²=30.25 * 3.141592... in²≈
≈95.0 in².
answer : c 95.0 in²
In my opinion I think you would be able to make atleast 2 outfits
Smallest number of cakes that each would have decorated is 18.
A number is prime if its only divisors are 1 and the number itself.
Out of your numbers, 36 and 38 are even, and thus divisible by 2, so they aren't prime.
Similarly, 35 ends with 5, so it's divisible by 5, and is not prime.
37 is divisible only by 1 and 37, and thus it's prime.
