Answer:
a) The gradient of a function is the vector of partial derivatives. Then
b) It's enough evaluate P in the gradient.
c) The directional derivative of f at P in direction of V is the dot produtc of 
and v.
![\nabla f(P) v=(-4,-4)\left[\begin{array}{ccc}2\\3\end{array}\right] =(-4)2+(-4)3=-20](https://tex.z-dn.net/?f=%5Cnabla%20f%28P%29%20v%3D%28-4%2C-4%29%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%5C%5C3%5Cend%7Barray%7D%5Cright%5D%20%3D%28-4%292%2B%28-4%293%3D-20)
d) The maximum rate of change of f at P is the magnitude of the gradient vector at P.
e) The maximum rate of change occurs in the direction of the gradient. Then
is the direction vector in which the maximum rate of change occurs at P.
Answer: hole at x = 0, asymptotes at x = -2 and x = -3
<u>Step-by-step explanation:</u>
= 
= 
x ≠ 0 ---> the x cancels out so this is a hole
x + 2 ≠ 0 ---> x ≠ -2 ---> asymptote at x = -2
x + 3 ≠ 0 ---> x ≠ -3 ---> asymptote at x = -3
THN forms a strait line with MHT so they would equal 180 when added.
180-126 = 54
The answer is C
Answer:
I thank it is 12 4/5
Step-by-step explanation:
hope this helps if not please let me now and dont worry about brainliest my main focus is just helping people.
The function f(t) that describes this scenario will be A = -42.57t + 1399.28
- Let the amount of oil remaining after time t be A
- Let the time taken be "t"
This required linear expression will be given as A= mt + b
Writing the gallons of oil and the time taken as a coordinate point (A, t), these are given as (11, 931) and (18, 633)
m is the rate of change = 633-931/18-11
m = -298/7
m = -42.57
Get the intercept;
633 = -42.57(18) + b
633 = -766.29 + b
b = 1,399.28
Heence the function f(t) that describes this scenario will be A = -42.57t + 1399.28
Learn more on functions here; brainly.com/question/17431959
