Answer: 8.6:8.6
Explanation:
1:n is the form you want.
n is 8.6. change the n value so it is 1:8.6
1 is 1 times bigger than 8.6
8.6 times 1 is 8.6
so you've got 8.6:8.6
your welcome, i hope this helps
8X+6Y=12
Here's how you solve it:
Just isolate y by itself to get y-intercept form.
This is the formula: Y=MX+B
M is the slope or the number next to X in the original problem.
First:
6Y=-8X+12
Next:
divided everything by 6
Y=-4/3+2
I think the answer is A!
Answer:
D)The range of f(x) includes values such that y ≥ 1, so the domain of f–1(x) includes values such that x ≥ 1.
Step-by-step explanation:
The missing tables are:
First table
x: 0 1 2
f(x): 1 10 100
Second table
x: 1000 100 10
f^-1(x): 3 2 1
Option A is not correct because f(x) has a y-intercept at (0, 1)
If f(x) has a y-intercept, then f^-1(x) has a x-intercept, which is located at (1, 0). Then option B is not correct
Option C is not correct because the domain of f^-1(x) is associated with x values.
Option D is correct because the domain of f(x) is the range of f^-1(x) and vice versa
For the first 6, we see that it is exactly one place behind the decimal point, therefore meaning that it is in the tenths place. The second 6 is three places behind the decimal place making it in the thousandths place. The third and final 6 is one place in front of the decimal, therefore it is in the ones place. Hope this helps!
Answer: the angle is 1°+n×120°
1°, 121°, 241°
Step-by-step explanation:
Angles are taken modulo 360°, so 363° = 3°.
Angle plus supplement gives 180°.
Let a be angle, s be supplement of a.
So s = 180-a. Given a = 3 + 2s
a = 3 + 2(180 - a)
a = 3 + 360 - 2a = 363 - 2a
3a = 363° or 3° or 723°
a = 121° or 1° or 241°
a = 1°
s = 179°
2s = 358°
2s+3 = 361° = 1° (modulo 360)
a = 121°
s = 180-121 = 59°
2s = 118°
2s + 3 = 121°, as required.
a = 241°
s = 360+180-241 = 540-241 = 299
2s = 598
2s + 3 = 601 = 241 (modulo 360)
