2 years ago

Which exponential function has a growth factor of One-half?

Mathematics

1 answer:

Gemiola [76]2 years ago

3 0

Answer:

An exponential function with a growth factor of 1/2 would have 1.5^x as part of it.

The exponential growth function is as follows.

r is the rate of growth (0.50)

You might be interested in

there are 30 students in the classand 24 of these students pass their english test.what percentage of these students pass their

GaryK [48]

Step-by-step explanation:

Total students-30

No.of students pass their English test-24

24/30 X 100=80%

So,80%students pass their test

5 0

2 years ago

How do I find vertex

algol13

Answer:

Get the equation in the form y = ax2 + bx + c.

Calculate -b / 2a. This is the x-coordinate of the vertex.

To find the y-coordinate of the vertex, simply plug the value of -b / 2a into the equation for x and solve for y.

Step-by-step explanation:

6 0

3 years ago

A magazine printed photos of three celebrities along with three photos of the celebrities as babies. The baby pictures did not i

LenaWriter [7]

You have a 33.33% chance to get it right each time
multiply 33.33%*33.33%*33.33%= .3333*.3333*.3333
it equals about 4%

6 0

3 years ago

If you apply the changes below to the absolute value parent function, f(x) = [xl,

TEA [102]

Answer: g(x)=|x+8|-3

Questions please feel free to ask. Thanks

7 0

3 years ago

Find the domain of the function. (Enter your answer using interval notation.)

Andreas93 [3]

Answer:

$(-\infty,-9)\cup(-9,\infty)$

Step-by-step explanation:

The domain of a rational function is all real numbers <em>except </em>for when the denominator equals 0.

So, to find the domain restrictions, set the denominator to 0 and solve for x.

We have the rational function:

$s(y)=\frac{7y}{y+9}$

Set the denominator to 0:

$y+9=0$

Subtract 9:

$y\neq-9$

So, the domain is all real numbers except for -9.

In other words, our domain is all values to the left of negative 9 and to the right of negative 9.

In interval notation, this is:

$(-\infty,-9)\cup(-9,\infty)$

And we're done :)

4 0

3 years ago