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Dafna1 [17]
4 years ago
10

PLEASE ANSWER ASAP!!!

Mathematics
1 answer:
qwelly [4]4 years ago
5 0

Answer:

D, E

Step-by-step explanation:

It’s not A because the equation can not be any pair of numbers.

It’s not B because that is stupid logic.

It’s not C because (3,4) and (10,8) don’t work

It’s not F because there is 1 solution

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Can you guys help me with the second one please :( . <br> I’ll mark you as a brainliest
Dennis_Churaev [7]

Answer:

x=30° y=150°

Step-by-step explanation:

The inside angles of a triangle always add up to 180. So 65+85+x=180. x would equal 30. Next a line is always 180 degrees. So to two angles on the line must total to 180 degrees. We know x is 30 degrees, so y is the remaining angle. 30 + y = 180. y is 150.

7 0
3 years ago
Read 2 more answers
Complete the following.
Gnom [1K]

Answer:

Step-by-step explanation:

1) From the given right angle triangle,

22 represents the hypotenuse of the right angle triangle.

With m∠21 as the reference angle,

x represents the opposite side of the right angle triangle.

To determine x, we would apply

the Sine trigonometric ratio.

Sin θ = opposite side/hypotenuse. Therefore,

Sin 21 = x/22

x = 22 Sin 21 = 22 × 0.3584

x = 7.9

2) From the given right angle triangle,

RS represents the hypotenuse of the right angle triangle.

With m∠S as the reference angle,

x represents the adjacent side of the right angle triangle.

To determine x, we would apply

the Cosine trigonometric ratio.

Cos θ = adjacent side/hypotenuse. Therefore,

Cos 33 = x/15

x = 15 Cos 33 = 15 × 0.8387

x = 12.6

3) From the given right angle triangle,

AB represents the hypotenuse of the right angle triangle.

With m∠A as the reference angle,

x represents the adjacent side of the right angle triangle.

y represents the opposite side of the right angle triangle.

To determine x, we would apply

the Cosine trigonometric ratio.

Cos θ = adjacent side/hypotenuse. Therefore,

Cos 32 = x/10

x = 10 Cos 32 = 10 × 0.848

x = 8.5

To determine y, we would apply

the Sine trigonometric ratio.

Sin θ = opposite side/hypotenuse. Therefore,

Sin 32 = y/10

y = 10 Sin 32 = 10 × 0.5299

y = 0.53

5 0
3 years ago
Write your answer in simplest radical form​
Licemer1 [7]

Answer:

a = 4\sqrt{3}

Step-by-step explanation:

Using the cosine ratio in the right triangle and the exact value

cos60° = \frac{1}{2} , then

cos60° = \frac{adjacent}{hypotenuse} = \frac{2\sqrt{3} }{a} = \frac{1}{2} ( cross- multiply )

a = 4\sqrt{3}

3 0
3 years ago
Could some explain the sandwich theorem (calculus/ limits)
den301095 [7]
\bf \textit{we know the range for }cos\left( \frac{1}{x} \right)\textit{ is }[-1,1]\textit{ therefore}&#10;\\\\\\&#10;-1~\ \textless \ ~cos\left( \frac{1}{x} \right)~\ \textless \ ~1\impliedby \textit{multiplying all sides by }x^2&#10;\\\\\\&#10;-1x^2~\ \textless \ ~x^2cos\left( \frac{1}{x} \right)~\ \textless \ ~1x^2\implies -x^2~\ \textless \ ~x^2cos\left( \frac{1}{x} \right)~\ \textless \ ~x^2

if the limit of -x² goes to "something", and the limit of x² goes to the same "something", if their limit coincide, and yet they're bounding the cosine expression, therefore, since the cosine expression is "sandwiched" between -x² and x², then the cosine expression "squeezes in" that little sliver between both -x² and x², and will inevitably go to the same limit.

\bf \begin{array}{ccccc}&#10;\lim\limits_{x\to 0} -x^2&\ \textless \ &x^2cos\left( \frac{1}{x} \right)&\ \textless \ &\lim\limits_{x\to 0} x^2\\&#10;\downarrow &&&&\downarrow \\&#10;0&&&&0\\&#10;&&\lim\limits_{x\to 0}x^2cos\left( \frac{1}{x} \right)\\&#10;&&\downarrow \\&#10;&&0&#10;\end{array}
7 0
3 years ago
Each square in Figures D and E has a side length of 1 unit. Compare the area of the two figures. Which figure has more area? How
dsp73

Option B has more, if you want to have mathematical work just set each of the square side lengths to 1. In the first figure, you have 4 units square for each square so 2 units sq on the first and 4 on the second. Then since the other shapes are half circles or 1/4 circles we can put them together to get full and partial circles. The first shape had 2 full circles and the second shape has 1.5. SO using 1 as the radius, you get 3.14 units sq per circle. Leaving you with (<em>circles) </em>6.28 + <em>(squares)</em> 2 leaving you with 8.28 units sq for figure 1 and <em>(circles)</em> 4.71  + <em>(squares)</em> 4 leaving you with 8.71 for figure 2. This leaves you with a .43 difference. Hope this helps

4 0
3 years ago
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