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Vikki [24]
3 years ago
14

On a cold January day, Mavis noticed that the temperature dropped 21 degrees over the course of the day to 9 degrees Celcius. Wr

ite an equation to determine what the temperature was at the beginning of the day.
Mathematics
1 answer:
uranmaximum [27]3 years ago
3 0

Answer:

-9 + 21 = t t = 12°C.

Step-by-step explanation:

For this problem lets have t be equal to the original temperature in the beginning of the day. The equation -9 + 21 = t represents this situation because it states that if we add the degrees that dropped to the current degrees  it will give us our original degrees. Solve. -9 + 21 = t (Simply add -9 + 21) -9 + 21 = (+12) 12 = t So, the original degrees in the beginning of the day was 12°C.

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Answer:

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Step-by-step explanation:

Given function,

g(x) = -\frac{2}{3}x-5

Step 1 : Replace g(x) by y:

y = -\frac{2}{3}x-5

Step 2 : Swap x and y:

x = -\frac{2}{3}y-5

Step 3 : Solve the equation for y ( isolate y in the left side ):

x +\frac{2}{3}y=-5

     \frac{2}{3}y=-5-x

      y=\frac{3}{2}(-5-x)

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      y=-\frac{3}{2}x-\frac{15}{2}

Step 4: Replace y by g^{-1}(x):

g^{-1}(x)=-\frac{3}{2}x-\frac{15}{2}

Hence, the inverse of the function g(x) is g^{-1}(x)=-\frac{3}{2}x-\frac{15}{2}.

8 0
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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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