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Jet001 [13]
3 years ago
13

Write the standard equation of a circle with center (0,0) and radius 7

Mathematics
2 answers:
Travka [436]3 years ago
8 0

Answer:

x² + y² = 49

Step-by-step explanation:

(x - 0)² + (y - 0)² = 7²

x² + y² = 49

lana66690 [7]3 years ago
7 0

Answer:

x^2 + y^2 = 49

Step-by-step explanation:

For center (h,k) and radius r, eqution of the respective circle is

(x-h)^2 + (y-k)^2 = r^2

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Between 0 degrees Celsius and 30 degrees Celsius, the volume V (in cubic centimeters) of 1 kg of water at a temperature T is giv
Ira Lisetskai [31]

Answer:

T = 3.967 C

Step-by-step explanation:

Density = mass / volume

Use the mass = 1kg and volume as the equation given V, we will come up with the following equation

D = 1 / 999.87−0.06426T+0.0085043T^2−0.0000679T^3

   = (999.87−0.06426T+0.0085043T^2−0.0000679T^3)^-1

Find the first derivative of D with respect to temperature T

dD/dT = \dfrac{70000000\left(291T^2-24298T+91800\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^2}

Let dD/dT = 0 to find the critical value we will get

\dfrac{70000000\left(291T^2-24298T+91800\right)}  = 0

Using formula of quadratic, we get the roots:

T =  79.53 and T = 3.967

Since the temperature is only between 0 and 30, pick T = 3.967

Find 2nd derivative to check whether the equation will have maximum value:

-\dfrac{140000000\left(395178T^4-65993368T^3+3286558821T^2+2886200857800T-121415215620000\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^3}

Substituting the value with T=3.967,

d2D/dT2 = -1.54 x 10^(-8)    a negative value. Hence It is a maximum value

Substitute T =3.967 into equation V, we get V = 0.001 i.e. the volume when the the density is the highest is at 0.001 m3 with density of

D = 1/0.001 = 1000 kg/m3

Therefore T = 3.967 C

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A package of 6 pairs of insulated gloves costs 38.34. What is the unit price of the pairs of gloves?
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divide the total cost by the total amount of the item for the unit price:

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