Answer: A. "Segment AD bisects angle CAB." is the right answer.
Step-by-step explanation:
Given : In ΔABC ,AC≅AB.
⇒∠ACB=∠CBA....(1) (∵ angles opposite to equal sides of a triangle are equal )
Now in ΔACD and ΔABD
AD=AD (common)....(2)
Here we need one more statement to prove the triangles congruent that is only statement (A) fits in it.
If AD bisects ∠CAB then ∠CAD=∠BAD..(3)
Now again Now in ΔACD and ΔABD
∠ACB=∠CBA [from (1)]
AD=AD [common]
∠CAD=∠BAD [from (3)]
So by ASA congruency criteria ΔADC≅ΔABD.
Multiply both sides by 2.3, ( tan 6° x 2.3 = f )
Regroup terms, 2.3 tan 6 = f.
F = 2.3 tan 6°
So the answer is tan 6 = tan 6 I think
Answer:
True
12+7>9(2-3)-8
19> (-9)-8
19>-17
Step-by-step explanation:
