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Inessa05 [86]
3 years ago
9

Students were asked to choose their favorite food and 4/8 of the students choose pizza and tacos . If 2/8 of the students chose

pizza , what faction chose tacos?

Mathematics
1 answer:
Svetach [21]3 years ago
7 0

The solution is in the attachment

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13x+y=4 plz help i cant get it right lol
kati45 [8]

Answer:

4

__

13

Step-by-step explanation:

look up top for explanation

7 0
3 years ago
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What is the value of x in the trangle? Enter your answer in the box. Round your final answer to the nearest hundredth.​
-Dominant- [34]

Use trigonometry.

cos(18°) = x/25

Multiply both sides by 25.

cos(18°)25 = x

23.7764129074 = x

We round off to the nearest hundredth. This means to round off to two decimal places.

Doing so, we get 23,78 cm = x.

4 0
3 years ago
Rectangle ABCD with coordinates A(1, 1), B(4, 1), C(4, 2), and D(1, 2) dilates with respect to the origin to give rectangle A'B'
IgorC [24]
Rectangle ABCD
Line AB = 4 - 1 = 3
Line CD = 4 - 1 = 3
Line AC = 2 - 1 = 1
Line BD = 2 - 1= 1

If line A'B' = 6

the scale factor of the dilation is 2.

Line AB: 3 x 2 = 6 line A'B/
5 0
3 years ago
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How many pairs of whole numbers have sum of 110
alisha [4.7K]
Because the number is even, then the number of possible combinations will be: 110/2 = 55 let's consider a simpler example, the number: 10, then we have: 10+0, 9+1, 8+2, 7+3, 6+4, which is equal to 10/2 =5 combinations. Note: We are not considering permutations between the elements of the sum therefore 10+0, 0+10 counts as one combination.
7 0
3 years ago
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Tough one!
frosja888 [35]
Imx->0 (asin2x + b log(cosx))/x4 = 1/2 [0/0 form] ,applying L'Hospital rule ,we get

= > limx->0 (2a*sinx*cosx - (b /cosx)*sinx)/ 4x3 = 1/2 => limx->0 (a*sin2x - b*tanx)/ 4x3 = 1/2 [0/0 form],

applying L'Hospital rule again ,we get,

 = > limx->0 (2a*cos2x - b*sec2x) / 12x2 = 1/2

For above limit to exist,Numerator must be zero so that we get [0/0 form] & we can further proceed.

Hence 2a - b =0 => 2a = b ------(A)

limx->0 (b*cos2x - b*sec2x) / 12x2 = 1/2 [0/0 form], applying L'Hospital rule again ,we get,

= > limx->0 b*(-2sin2x - 2secx*secx.tanx) / 24x = 1/2 => limx->0 2b*[-sin2x - (1+tan2x)tanx] / 24x = 1/2

[0/0 form], applying L'Hospital rule again ,we get,

limx->0 2b*[-2cos2x - (sec2x+3tan2x*sec2x)] / 24 = 1/2 = > 2b[-2 -1] / 24 = 1/2 => -6b/24 = 1/2 => b = -2

from (A), we have , 2a = b => 2a = -2 => a = -1

Hence a =-1 & b = -2
7 0
3 years ago
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