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Mekhanik [1.2K]
3 years ago
10

\times \sqrt{22} " alt="3 \sqrt{50} \times \sqrt{22} " align="absmiddle" class="latex-formula">
A
15 \sqrt{22}
B
30 \sqrt{22}
C
30 \sqrt{11}
D
15 \sqrt{11}

​
Mathematics
1 answer:
wariber [46]3 years ago
6 0

Answer:I'm 97.248316478692% sure it's C.

Step-by-step explanation:

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The lines are intersected at point (0, -5). So (0, -5) is the solution.

Answer is the third one

(0,-5 )

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Phil has 7 quarts of hot chocolate to give his class mates. how many of phils friend's can have one cup of hot chocolate
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4 cups per quarter

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One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times sm
sergey [27]

One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle. Then the lines are parallel

<h3><u>Solution:</u></h3>

Given that, One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle.  

We have to prove that the lines are parallel.

If they are parallel, sum of the described angles should be equal to 180 as they are same side exterior angles.

Now, the 1st angle will be 1/6 of right angle is given as:

\begin{array}{l}{\rightarrow 1^{\text {st }} \text { angle }=\frac{1}{6} \times 90} \\\\ {\rightarrow 1^{\text {st }} \text { angle }=15 \text { degrees }}\end{array}

And now, 15 degrees is 11 times smaller than the other  

Then other angle = 11 times of 15 degrees

\text {Other angle }=11 \times 15=165 \text { degrees }

Now, sum of angles = 15 + 165 = 180 degrees.

As we expected their sum is 180 degrees. So the lines are parallel.

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5 0
4 years ago
Suppose you do an analysis of the starting salaries of 100 recent Lehman graduates. You find that the average starting salary is
madreJ [45]

Answer:

a) (59180,60820)

b) (59020,60980)        

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $60,000

Standard Deviation, σ = $5,000

Sample size, n = 100

a) 90% critical values

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.10} = 1.64

60000 \pm 1.64(\frac{5000}{\sqrt{100}} ) = 60000 \pm 820 = (59180,60820)

b) 95% critical values

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

60000 \pm 1.96(\frac{5000}{\sqrt{100}} ) = 60000 \pm 980= (59020,60980)

5 0
3 years ago
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