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2 years ago

Marisa painted of her bedroom in of an hour. At this rate, how long would it take her to paint the entire room

Mathematics

1 answer:

LenaWriter [7]2 years ago

6 0

I don't know the details like how much of the room she painted and how long she took. So there is no possible answer

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ASAP what is the quotient of 1 divided by the fraction 4/3

Virty [35]

Answer:

0.75

Step-by-step explanation:

6 0

3 years ago

Which of the following numbers is irrational? -9/5 , sqrt (5) , 7/3 , sqrt (9)

kirza4 [7]

Sqrt 5 because it’s an imperfect square. Fractions with integers are always rational and sqrt 9 is perfect so it is also an integer.

8 0

3 years ago

Read 2 more answers

Which of these terms is unlike the others? 4b, b, 4, 7b A. 4b B. b C. 4 D. 7b

olga_2 [115]

Answer:

C. 4

Step-by-step explanation:

All other answer choices involve the variable 'b' and/or are tied to it in some way. The sole number 4 has no connection to the variable b, therefore it is C. 4.

5 0

3 years ago

Please help please please

alexgriva [62]

Two sets (or three technically)
sets {2, 4, 6, 8, 10} & {8,9,10}

The probability of one of the above numbers because it is a union of those two vars/sets so numbers from either set go

{2, 4, 6, 8, 9, 10}
Thats 6 of the 10 numbers

6/10
.6

If i'm wrong, sorry, haven't done this kind of stuff in a while

8 0

3 years ago

Suppose that one person in 10,000 people has a rare genetic disease. There is an excellent test for the disease; 98.8% of the pe

nirvana33 [79]

Answer:

A)The probability that someone who tests positive has the disease is 0.9995

B)The probability that someone who tests negative does not have the disease is 0.99999

Step-by-step explanation:

Let D be the event that a person has a disease

Let $D^c$ be the event that a person don't have a disease

Let A be the event that a person is tested positive for that disease.

P(D|A) = Probability that someone has a disease given that he tests positive.

We are given that There is an excellent test for the disease; 98.8% of the people with the disease test positive

So, P(A|D)=probability that a person is tested positive given he has a disease = 0.988

We are also given that one person in 10,000 people has a rare genetic disease.

So, $P(D)=\frac{1}{10000}$

Only 0.4% of the people who don't have it test positive.

$P(A|D^c)$ = probability that a person is tested positive given he don't have a disease = 0.004

$P(D^c)=1-\frac{1}{10000}$

Formula: $P(D|A)=\frac{P(A|D)P(D)}{P(A|D)P(D^c)+P(A|D^c)P(D^c)}$

$P(D|A)=\frac{0.988 \times \frac{1}{10000}}{0.988 \times (1-\frac{1}{10000}))+0.004 \times (1-\frac{1}{10000})}$

P(D|A)= $\frac{2470}{2471}$ =0.9995

P(D|A)= $0.9995$

A)The probability that someone who tests positive has the disease is 0.9995

(B)

$P(D^c|A^c)$ =probability that someone does not have disease given that he tests negative

$P(A^c|D^c)$ =probability that a person tests negative given that he does not have disease =1-0.004

=0.996

$P(A^c|D)$ =probability that a person tests negative given that he has a disease =1-0.988=0.012

Formula: $P(D^c|A^c)=\frac{P(A^c|D^c)P(D^c)}{P(A^c|D^c)P(D^c)+P(A^c|D)P(D)}$

$P(D^c|A^c)=\frac{0.996 \times (1-\frac{1}{10000})}{0.996 \times (1-\frac{1}{10000})+0.012 \times \frac{1}{1000}}$

$P(D^c|A^c)=0.99999$

B)The probability that someone who tests negative does not have the disease is 0.99999

8 0

3 years ago