Simplify 6^-3/6^5answers:• 6^8• 6^-2• 1/6^8• 1/6^2

Mathematics

1 answer:

Katyanochek1 [597]2 years ago

7 0

When you divide same numbers with exponents you would subtract the exponent: a^2/a^1 = a^(2-1) = a

Therefore: 6^-3/6^5 = 6^(-3-5) = 6^-8
Which is also 1/6^8

Solution: C

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Answer:

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Step-by-step explanation:

Tha most appropiate distribution to model the probability of this events is the exponential distribution.

The cumulative distribution function of the exponential distribution is given by:

$P(t$

The destructive earthquakes happen in average once a year. This can be expressed by the parameter λ=1/year.

We can express the probability of having a 3 month period (t=3/12=0.25) without destructive earthquakes as:

$P(t>0.25)=1-P(t$

Applying the memory-less property of the exponential distribution, in which the past events don't affect the future probabilities, the probability of having at least 7 months (t=0.58) elapsed before the first earthquake given that 3 months have already elapsed, is the same as the probability of having 4 months elapsed before an earthquake.

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