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2 years ago

Simplify 6^-3/6^5answers:• 6^8• 6^-2• 1/6^8• 1/6^2

Mathematics

1 answer:

Katyanochek1 [597]2 years ago

7 0

When you divide same numbers with exponents you would subtract the exponent: a^2/a^1 = a^(2-1) = a

Therefore: 6^-3/6^5 = 6^(-3-5) = 6^-8
Which is also 1/6^8

Solution: C

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1 year ago

6x - 2(x + 2) > 2 - 3(x+3)<br><br>Solve the inequality <br><br>plz help

Mumz [18]

Answer:

x > -3/7

Step-by-step explanation:

6x - 2(x + 2) > 2 - 3(x + 3)

Distribute the two and three inside the parenthesis.

6x - 2x - 4 > 2 - 3x - 9

Combine like terms.

4x - 4 > -3x - 7

Add 4 to both sides.

4x > -3x - 3

Add 3x to both sides.

7x > -3

Divide both sides by 7.

x > -3/7

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3 years ago

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I got 5 packages as the answer

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4 years ago

For 0 ≤ ϴ < 2π, how many solutions are there to tan(StartFraction theta Over 2 EndFraction) = sin(ϴ)? Note: Do not include va

Black_prince [1.1K]

Answer:

3 solutions:

$\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}$

Step-by-step explanation:

So, first of all, we need to figure the angles that cannot be included in our answers out. The only function in the equation that isn't defined for some angles is $tan(\frac{\theta}{2})$ so let's focus on that part of the equation first.

We know that:

$tan(\frac{\theta}{2})=\frac{sin(\frac{\theta}{2})}{cos(\frac{\theta}{2})}$

therefore:

$cos(\frac{\theta}{2})\neq0$

so we need to find the angles that will make the cos function equal to zero. So we get:

$cos(\frac{\theta}{2})=0$

$\frac{\theta}{2}=cos^{-1}(0)$

$\frac{\theta}{2}=\frac{\pi}{2}+\pi n$

$\theta=\pi+2\pi n$

we can now start plugging values in for n:

$\theta=\pi+2\pi (0)=\pi$

if we plugged any value greater than 0, we would end up with an angle that is greater than $2\pi$ so, that's the only angle we cannot include in our answer set, so:

$\theta\neq \pi$

having said this, we can now start solving the equation:

$tan(\frac{\theta}{2})=sin(\theta)$

we can start solving this equation by using the half angle formula, such a formula tells us the following:

$tan(\frac{\theta}{2})=\frac{1-cos(\theta)}{sin(\theta)}$

so we can substitute it into our equation:

$\frac{1-cos(\theta)}{sin(\theta)}=sin(\theta)$

we can now multiply both sides of the equation by $sin(\theta)$

so we get:

$1-cos(\theta)=sin^{2}(\theta)$

we can use the pythagorean identity to rewrite $sin^{2}(\theta)$ in terms of cos:

$sin^{2}(\theta)=1-cos^{2}(\theta)$

so we get:

$1-cos(\theta)=1-cos^{2}(\theta)$

we can subtract a 1 from both sides of the equation so we end up with:

$-cos(\theta)=-cos^{2}(\theta)$

and we can now add $cos^{2}(\theta)$

to both sides of the equation so we get:

$cos^{2}(\theta)-cos(\theta)=0$

and we can solve this equation by factoring. We can factor $cos(\theta)$ to get:

$cos(\theta)(cos(\theta)-1)=0$

and we can use the zero product property to solve this, so we get two equations:

Equation 1:

$cos(\theta)=0$

$\theta=cos^{-1}(0)$

$\theta={\frac{\pi}{2}, \frac{3\pi}{2}}$

Equation 2:

$cos(\theta)-1=0$

we add a 1 to both sides of the equation so we get:

$cos(\theta)=1$

$\theta=cos^{-1}(1)$

$\theta=0$

so we end up with three answers to this equation:

$\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}$

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3 years ago

Can someone explain or help me out

Akimi4 [234]

Answer:

The bird has to fly 7.5 m

Step-by-step explanation:

Please see diagram in attached image.

Notice that there is a right angle triangle that defines the situation, and you know two elements of such triangle;

1) one acute angle ( $15^o$ ), and

2) the side opposite to that angle.

What you need to find is the side adjacent to the angle, which is what the bird needs to fly horizontally to be above the fish. We named that "x".

The trig function that relates such triangle elements is the tangent:

$tan(\theta)=\frac{opposite}{adjacent} \\tan(15^o)=\frac{2\,m}{x} \\x=\frac{2\,m}{tan(15^o)} \\x=7.46 \,\,m$

which rounded to the nearest tenth is: 7.5 m

8 0

3 years ago

Simplify 6^-3/6^5answers:• 6^8• 6^-2• 1/6^8• 1/6^2​

Simplify 6^-3/6^5answers:• 6^8• 6^-2• 1/6^8• 1/6^2