All categories

3 years ago

Will mark brainlyist or however you spell it

Mathematics

1 answer:

eimsori [14]3 years ago

6 0

Your answer should be C! Hope that helps

You might be interested in

Please help with this question

Alchen [17]

$T = 2\pi \sqrt{\dfrac{L}{32}}$

$\dfrac{T}{2\pi} = \sqrt{\dfrac{L}{32}}$

$L = \dfrac{32 T^2}{4\pi^2} = \dfrac{8T^2}{\pi^2}$

$L = \dfrac{32 (2.2)^2}{4(3.14)^2} =3.927 \textrm{ feet}$

Second choice: 4 feet

8 0

4 years ago

What is the solution to this equation? Round your answer to two decimal

mel-nik [20]

Answer:

See attachment. Also, I got 2.36 as the answer with my calculator despite that not being on the multiple choice list

5 0

2 years ago

Read 2 more answers

X+5y=-23<br> X-y=1<br> Solve by elemination

tiny-mole [99]

Answer:

Negative 4

-4

Step-by-step explanation:

x+5= -23

-x+y= -1

6y= -24

-24÷6= -4

7 0

3 years ago

Read 2 more answers

Robert Bentley owns and operates the Bentley Clothing Store. A traditional income statement is shown below. There is no outstand

siniylev [52]

Answer:

12x+4x-7y+45b+78a-44b+1a+1z+0d+1.1a+1.1a

5 0

2 years ago

Find a power series representation for the function. (give your power series representation centered at x = 0. ) f(x) = ln(5 − x

klio [65]

Recall that for $|x|$ , we have the convergent geometric series

$\displaystyle \sum_{n=0}^\infty x^n = \frac1{1-x}$

Now, for $\left|\frac x5\right| < 1$ , we have

$\dfrac1{5 - x} = \dfrac15 \cdot \dfrac1{1 - \frac x5} = \dfrac15 \displaystyle \sum_{n=0}^\infty \left(\frac x5\right)^n = \sum_{n=0}^\infty \frac{x^n}{5^{n+1}}$

Integrating both sides gives

$\displaystyle \int \frac{dx}{5-x} = C + \int \sum_{n=0}^\infty \frac{x^n}{5^{n+1}} \, dx$

$\displaystyle -\ln(5-x) = C + \sum_{n=0}^\infty \frac{x^{n+1}}{5^{n+1}(n+1)}$

If we let $x=0$ , the sum on the right side drops out and we're left with $C=-\ln(5)$ .

It follows that

$\displaystyle \ln(5-x) = \ln(5) - \sum_{n=0}^\infty \frac{x^{n+1}}{5^{n+1}(n+1)}$

$\displaystyle \ln(5-x) = \boxed{\ln(5) - \sum_{n=1}^\infty \frac{x^n}{5^n n}}$

3 0

2 years ago