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ad-work [718]
3 years ago
5

Distance between (4,8) and (9,20)

Mathematics
1 answer:
DanielleElmas [232]3 years ago
4 0
That’s cald midpoint, x= 6.5 y=14
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What is the equation, in point-slope form, for a line that goes through(8,
LUCKY_DIMON [66]

Answer:

\boxed{y-4=-\frac{5}{6}(x-8)}

Step-by-step explanation:

Point slope form is: y-y_1=m(x-x_1)

(x_1,y_1) - Coordinate\\ m- Slope

We are given the slope of -\frac{5}{6} and the point of (8,4).

Replace 'm' with -5/6, 'x1' with 8, and 'y1' with 4.

y-y_1=m(x-x_1)\rightarrow \boxed{y-4=-\frac{5}{6}(x-8)}

I do not see any options that match this, but the boxed equation should the correct answer.

8 0
3 years ago
The diagram below shows twelve 30-60-90 triangles placed in a circle so that the hypotenuse of each triangle coincides with the
julia-pushkina [17]

Answer:

m+n = 337

Step-by-step explanation:

Lets start from the first triangle, It is given to be as 30-60-90.

The hypotenous of first rectangle be 2x, then other sides are by default x and

\sqrt{3}(x) , using laws of trigonometry.

(sin(30) = 0.5  and cos(30) = \frac{\sqrt{3}}{2})

The perimeter of first triangle is ,

= 2x + x + \sqrt{3}(x) = x(3+\sqrt{3}) = \sqrt{3}x(1+\sqrt{3})

Now, for second triangle, the longer leg is 2x, and similarly again,

other 2 sides are \frac{2x}{\sqrt{3}}  and \frac{4x}{\sqrt{3}}.

Again the perimeter of triangle comes out as,

= \sqrt{3}(x)(1+\sqrt{3})(\frac{2}{\sqrt{3}})

Thus, the repeating pattern is identified. The consecutive perimeters differ by, multiplying by factor \frac{2}{\sqrt{3}}

Thus, we can say that perimeter of 4th triangle is,

= (\frac{2}{\sqrt{3}})^{3}(X), where X is the repeating constant.

And of 12th triangle is,

= (\frac{2}{\sqrt{3}})^{11}(X),

Evaluating the above ratio, we get,

= \frac{81}{256}

Thus, m =256 and n=81.

Thus, m+n = 256+81 = 337.

6 0
3 years ago
Luther evaluated 2 with the exponent of 3 as 9 and Wade evaluated 3 with the exponent of 2 as 9. Are both students correct?
8090 [49]

Answer:

No.

Step-by-step explanation:

2^3 is 8. An easy way to check this is by doing 2*2*2.

3^2 however is 9 because 3*3 is 9

5 0
4 years ago
Which of the following is the equation of a circle with a radius of 10 cm and center at (–3, 6)?
vlabodo [156]

The equation of a circle is (x - h)² + (y - k)² = radius² where (h, k) is the ordered pair for the center.

(x - (- 3))² + (y - 6)² = 10²

(x + 3)² + (y - 6) = 100

5 0
4 years ago
Write the expression 2 3/5 as a radical.
BARSIC [14]
a^{\frac{m}{n}} = \sqrt[n]{a^m}

2^{\frac{3}{5}} = \sqrt[5]{2^3}

Answer is option D.
5 0
3 years ago
Read 2 more answers
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