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Vedmedyk [2.9K]
3 years ago
7

When placed in a 100-mL square box, a substance has a spherical shape and has a volume of 50 mL. When placed in a 100-mL circula

r tube, that same substance has a spherical shape and a 50-mL volume. In what phase or state was the substance?
Chemistry
1 answer:
ikadub [295]3 years ago
8 0

Solution: There are major three phases of substance, namely solid, liquid and gas.

Here, solid substances have definite shape, they are rigid and can not change their volume or shape if kept in any container.

Liquid substances do not have any shape of their own, they take shape of the container in which they are kept. They are compressible in nature.

Gaseous substances also do not have their own shape, the molecules of gas continuously move in the container in which they are stored. Gases are highly compressible in nature.

Here, a substance when placed in a 100-mL square box have spherical shape and 50 mL volume. The shape and volume of the substance do not change when it is placed in a 100-mL circular tube, that means it does not change the shape with change of container and the state of substance will be solid.


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Use Boyle’s law to complete the following:
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Answer:

The answer to your question is: 0.25 l

Explanation:

Data

P1 = 1 atm

V1 = 0.5 l

P2 =2 atm

V2 = ?

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Formula

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Clear V2 from the formula

            V2 = V1P1/P2

Substitution

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The vapor pressure of water at 65oC is 187.54 mmHg. What is the vapor pressure of a ethylene glycol (CH2(OH)CH2(OH)) solution ma
Pavlova-9 [17]

Answer:

173.83 mmHg is the vapor pressure of a ethylene glycol solution.

Explanation:

Vapor pressure of water at 65 °C=p_o= 187.54 mmHg

Vapor pressure of the solution at 65 °C= p_s

The relative lowering of vapor pressure of solution in which non volatile solute is dissolved is equal to mole fraction of solute in the solution.

Mass of ethylene glycol = 22.37 g

Mass of water in a solution = 82.21 g

Moles of water=n_1=\frac{82.21 g}{18 g/mol}=4.5672 mol

Moles of ethylene glycol=n_2=\frac{22.37 g}{62.07 g/mol}=0.3603 mol

\frac{p_o-p_s}{p_o}=\frac{n_2}{n_1+n_2}

\frac{187.54 mmHg-p_s}{187.54 mmHg}=\frac{0.3603 mol}{0.3603 mol+4.5672 mol}

p_s=173.83 mmHg

173.83 mmHg is the vapor pressure of a ethylene glycol solution.

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3 years ago
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