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Vedmedyk [2.9K]
3 years ago
7

When placed in a 100-mL square box, a substance has a spherical shape and has a volume of 50 mL. When placed in a 100-mL circula

r tube, that same substance has a spherical shape and a 50-mL volume. In what phase or state was the substance?
Chemistry
1 answer:
ikadub [295]3 years ago
8 0

Solution: There are major three phases of substance, namely solid, liquid and gas.

Here, solid substances have definite shape, they are rigid and can not change their volume or shape if kept in any container.

Liquid substances do not have any shape of their own, they take shape of the container in which they are kept. They are compressible in nature.

Gaseous substances also do not have their own shape, the molecules of gas continuously move in the container in which they are stored. Gases are highly compressible in nature.

Here, a substance when placed in a 100-mL square box have spherical shape and 50 mL volume. The shape and volume of the substance do not change when it is placed in a 100-mL circular tube, that means it does not change the shape with change of container and the state of substance will be solid.


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Answer:

26.99 % of air that will be displaced

Explanation:

Step 1: Data given

A 1.2-L container of liquid nitrogen is kept in a closet measuring 1.0m by 1.3m by 2.0m

Temperature = 23.5 °C

Atmospheric pressure = 1.2 atm

Liquid nitrogen has a density of 0.807 g/mL

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Step 2: Calculate mass of nitrogen

Mass of nitrogen = density * volume

Mass of nitrogen = 0.807 g/mL * 1200 mL

Mass of nitrogen = 968.4 grams

Step 3: Calculate moles of N2

Moles N2 = mass N2 / molar mass N2

Moles N2 = 968.4 grams /28 g/mol

Moles N2 = 34.586 moles

Step 4: Calculate volume

p*V = n*R*T

⇒ p = the the pressure = 1.2 atm

⇒ V = the volume of N2 = TO BE DETERMINED

⇒ n = the number of moles = 34.586 moles

⇒ R = the gas constant = 0.08206 L*atm/K*mol

⇒ T = the temperature = 23.5 °C = 296.65

V = (n*R*T)/p

V = (34.586 * 0.08206 * 296.65)/1.2

V = 701.61 L

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1.0 m * 1.3 m * 2 m = 2.6 m³ = 2600 L

Step 6: Calculate the percent volume displaced

(701.61 L  / 2600 L) * 100% = 26.99%

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